Error: Too many output arguments

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Barry Allen
Barry Allen on 25 Feb 2020
Edited: Stephen23 on 25 Feb 2020
I have written a code for my final year project . I called a crn(). I get a error that too many arguments. but when I run the function code alone, I get the output with single argument.
function crn(tow)
Q =20;
Pi=[0.3,0.4,0.2,0.5,0.4];
Pa=10;
%tow=0.5
Pdbar=15;
Y=4;
fs=10000;
yi=[1,3,5,2,3];
y1=[1,2,5,8,7];
y2=10;
yj=[2,3,4,5,2];
N=5;
z=sum(Pi(2:N).*yi(2:N));
S=(Pa*y2)/(1+z);
alpha=sqrt((2*Y)+1)*Q^-1*Pdbar;
a=sum(Pi(2:N).*y1(2:N));
yj=yj(3:N);
yj=[yj 0];
b=sum(Pi(2:N).*yj);
bet=sum(log2((1+(sum(Pi(2:N).*yi(2:N))/(1+b)))))-(a/(1+a));
A = ((1-(Q*(alpha+(sqrt(tow*fs)*Y))))+((1-tow)*((Y*sqrt(fs))/(2*sqrt(2*3.14)))*tow^(-0.5)*exp(-(alpha+(sqrt(tow*fs)*Y))^2)/2));
B = (log2(1+((tow*S)/(1-tow)))+((1-tow)*(1-(Q*(alpha+(sqrt(tow*fs)*Y))))*(S/(((bet+1)*(1-tow))+(S*tow))*(1-tow))));
dR_tow=((A*B*10^(-7))/3);
%disp(dR_tow);
end
T=1;
tow_min=0;
tow_max=T;
while (tow_max-tow_min)>0.02
tow_bar=(tow_max+tow_min)/2;
a=crn(tow_bar);
b=crn(tow_min);
if a==b
tow_min=tow_bar;
else
tow_max=tow_bar;
end
end
tow0=tow_bar;
disp("tow0="+tow);
  1 Comment
Stephen23
Stephen23 on 25 Feb 2020
Edited: Stephen23 on 25 Feb 2020
"...but when I run the function code alone, I get the output with single argument."
Nope.
At the end of your function you use disp to display something, but the function does not return any output arguments:

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Accepted Answer

Subhadeep Koley
Subhadeep Koley on 25 Feb 2020
Hi, this is because you function crn is not returning anything. If you want to return dR_tow then use the code below.
function dR_tow = crn(tow)
Q =20;
Pi=[0.3,0.4,0.2,0.5,0.4];
Pa=10;
%tow=0.5
Pdbar=15;
Y=4;
fs=10000;
yi=[1,3,5,2,3];
y1=[1,2,5,8,7];
y2=10;
yj=[2,3,4,5,2];
N=5;
z=sum(Pi(2:N).*yi(2:N));
S=(Pa*y2)/(1+z);
alpha=sqrt((2*Y)+1)*Q^-1*Pdbar;
a=sum(Pi(2:N).*y1(2:N));
yj=yj(3:N);
yj=[yj 0];
b=sum(Pi(2:N).*yj);
bet=sum(log2((1+(sum(Pi(2:N).*yi(2:N))/(1+b)))))-(a/(1+a));
A = ((1-(Q*(alpha+(sqrt(tow*fs)*Y))))+((1-tow)*((Y*sqrt(fs))/(2*sqrt(2*3.14)))*tow^(-0.5)*exp(-(alpha+(sqrt(tow*fs)*Y))^2)/2));
B = (log2(1+((tow*S)/(1-tow)))+((1-tow)*(1-(Q*(alpha+(sqrt(tow*fs)*Y))))*(S/(((bet+1)*(1-tow))+(S*tow))*(1-tow))));
dR_tow=((A*B*10^(-7))/3);
end
Hope this helps!

More Answers (1)

Andy
Andy on 25 Feb 2020
Assuming that the information you want to return is dR_tow, change the first line of the function to
function [dR_tow] = crn(tow)

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