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I have a matrix that contains strings and i have to find words in it.

7 Ansichten (letzte 30 Tage)
I have to create a program that gives you the position of the first letter of the word you input and if it's from left to right or right to left.
for example if you input the word 'er' it should tell you that:
The word was found from left to right at the position (1,1)
Please help
['e' 'r' 'd' 'u' 'o' 'p' 'i' 'e' 'c' 'e';...
't' 'p' 'r' 'o' 'm' 'e' 't' 'a' 'l' 'l';...
'i' 's' 'd' 'p' 's' 't' 'u' 'b' 'a' 'a';...
'g' 'e' 'p' 'o' 'm' 's' 'i' 'c' 'm' 'v';...
's' 't' 'e' 'i' 'u' 'r' 'a' 't' 'e' 'a';...
'o' 't' 'n' 'n' 'c' 'b' 'c' 'b' 'r' 'g';...
'u' 'e' 'f' 'c' 't' 'e' 'l' 'u' 'l' 'e';...
'v' 'l' 'i' 'o' 'r' 'b' 'r' 'o' 'i' 'e';...
'e' 'l' 'e' 'n' 'u' 'u' 'i' 'r' 'n' 't';...
'r' 'i' 'v' 'i' 'e' 'r' 'e' 'j' 'g' 'a';...
'a' 'a' 'r' 'n' 'e' 'l' 'r' 'r' 'o' 'c';...
'i' 'p' 'e' 'c' 'a' 'r' 'a' 't' 't' 'u';...
'n' 't' 'e' 'g' 'a' 'i' 'l' 'l' 'a' 'd';...
'f' 'i' 'l' 'o' 'n' 'o' 'l' 'a' 't' 'e']
  2 Kommentare
Mil Shastri
Mil Shastri am 19 Feb. 2020
Hi Ziyad, could you rephrase your question. It's not very clear.
Stephen23
Stephen23 am 3 Mär. 2020
Bearbeitet: Stephen23 am 3 Mär. 2020
The character array shown in the question can be written more simply as:
['erduopiece';...
'tprometall';...
'isdpstubaa';...
'gepomsicmv';...
'steiuratea';...
'otnncbcbrg';...
'uefctelule';...
'vliorbroie';...
'elenuuirnt';...
'rivierejga';...
'aarnelrroc';...
'ipecarattu';...
'ntegaillad';...
'filonolate']
or:
['erduopiece';'tprometall';'isdpstubaa';'gepomsicmv';'steiuratea';'otnncbcbrg';'uefctelule';'vliorbroie';'elenuuirnt';'rivierejga';'aarnelrroc';'ipecarattu';'ntegaillad';'filonolate']

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Akzeptierte Antwort

Jalaj Gambhir
Jalaj Gambhir am 3 Mär. 2020
Hi,
You can use strfind function to determine the presence of elements in you char array.
matrix = ['a','b','d','f';
'c','t','a','g';
'f','a','n','p';
'd','b','a','b'];
word = 'ab';
for i=1:length(matrix)
str = matrix(i,:);
idxL2R = strfind(str,word);
idxR2L = strfind(str,flip(word));
result = ['for string = ',str,' indexL2R while searching for word = ',word,
' is = ',int2str(idxL2R), ' indexR2L is = ', int2str(idxR2L)];
disp(result);
end
  2 Kommentare
Jalaj Gambhir
Jalaj Gambhir am 3 Mär. 2020
Result:
for string = abdf indexL2R while searching for word = ab is = 1 indexR2L is =
for string = ctag indexL2R while searching for word = ab is = indexR2L is =
for string = fanp indexL2R while searching for word = ab is = indexR2L is =
for string = dbab indexL2R while searching for word = ab is = 3 indexR2L is = 2
Ziyad Azouny
Ziyad Azouny am 6 Mär. 2020
Thank you very much for the answer :)

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Stephen23
Stephen23 am 3 Mär. 2020
>> mat = ['erduopiece';'tprometall';'isdpstubaa';'gepomsicmv';'steiuratea';'otnncbcbrg';'uefctelule';'vliorbroie';'elenuuirnt';'rivierejga';'aarnelrroc';'ipecarattu';'ntegaillad';'filonolate'];
>> baz = @(r,c)[r*ones(numel(c),1),c(:)];
>> vec = num2cell(1:size(mat,1));
>> fun = @(s)cell2mat(cellfun(baz,vec(:),strfind(num2cell(mat,2),s),'uni',0)).';
>> str = 'er';
>> fprintf('The word was found from left to right at the position (%u,%u)\n',fun(str))
The word was found from left to right at the position (1,1)
The word was found from left to right at the position (10,5)
>> fprintf('The word was found from right to left at the position (%u,%u)\n',fun(fliplr(str)))
The word was found from right to left at the position (10,6)

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