I really thanks in advance any help. I am trying to use the below command to find any variable from the A member of the B, but encountering with the error. Welcome any suggestion.
[~,JINDX] = cellfun(@(x)(ismember(B,x)),A,'Uni',false);
Error using cell/ismember (line 34)
Input A of class cell and input B of class char must be cell arrays of strings, unless one is a string.
Error in @(x)(ismember(B,x))
34 error(message('MATLAB:ISMEMBER:InputClass',class(a),class(b)));

1 Kommentar

Stephen23
Stephen23 am 18 Feb. 2020
Bearbeitet: Stephen23 am 18 Feb. 2020
It is not clear what you expect. Cell array A contains Rx1 character arrays,e.g.:
>> A{1}
ans =
6
9
0
0
8
0
5
while cell array B contains scalar numerics (which would be much better store in once numeric array):
>> B{1}
ans = 6900805
Do you expect that Rx1 character vector to be equivalent to that numeric scalar? For example:
>> Anum = str2double(cellfun(@(v)v(:).',A,'uni',0));
>> Bnum = [B{:}];
>> idx = ismember(Bnum,Anum)
idx =
1 0 0 0 0 0 0 0 0 0

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KSSV
KSSV am 18 Feb. 2020

0 Stimmen

load("example.mat") ;
N = length(A) ;
A1 =zeros(N,1) ;
for i = 1:N
A1(i) = str2num(A{i}') ;
end
B1 = cell2mat(B)' ;
[c,ia] = ismemebr(A1,B1) ;

6 Kommentare

Stephen23
Stephen23 am 18 Feb. 2020
@KSSV: you already know that str2double is preferred over str2num, and that it does not require a loop.
KSSV
KSSV am 18 Feb. 2020
Ohh..yes...
Farshid Daryabor
Farshid Daryabor am 18 Feb. 2020
Yes, replaced str2num to str2double. Thanks again
Farshid Daryabor
Farshid Daryabor am 18 Feb. 2020
Dear KSSV,
the problem is when I want to use ia as index to find the corresponding variable,
>> C = D(ia);
Subscript indices must either be real positive integers or logicals.
Show us the whole code...in the give answer
A1(c)
works fine.
Farshid Daryabor
Farshid Daryabor am 18 Feb. 2020
great, it's work to me also. Thanks

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