- Do you want a grid of (x,y) locations where the z value is a parabola? So it's like you have a bowl sitting above (or below) the x-y plane? Because if that's so, you don't need z. The I value is the z value, which is the distance from the x-y plane.
- Or do you want to do some kind of Delaunay triangulation of a set of (x,y,z) points to form a surface with a bunch of triangles on it?
Create a 3D mesh of a paraboloidal region
4 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I have a paraboloid region. I would like to plot this region and build a tetrahedron or Hexahedron mesh, for this I use:
a = 40;
d = 1;
x=-40:step:40;
y=-40:step:40;
z=-40:step:40;
I = 16*a^2.*y.^4+a.*y.^3.*(-32*a^2-8*d^2-8.*x.^2-8.*z.^2)+a.*y.*(32*a^2*d^2+8*d^4-8*a^2.*x.^2+2*d^2.*x.^2-10.*x.^4-8*a^2.*z.^2+2*d^2.*z.^2-20.*x.^2.*z.^2- 10.*z.^4)+y.^2.*(16*a^4-8*a^2*d^2+d^4+32*a^2.*x.^2-2*d^2.*x.^2+x.^4+32*a^2.*z.^2-2*d^2.*z.^2+2.*x.^2.*z.^2+z.^4)-(16.*a.^4.*d^2+8*a^2*d^4+d^6+20*a^2*d^2.*x.^2- 3*d^4.*x.^2-a^2.*x.^4+3*d^2.*x.^4-x.^6+20*a^2*d^2.*z.^2-3*d^4.*z.^2-2*a^2.*x.^2.*z.^2+6*d^2.*x.^2.*z.^2-3.*x.^4.*z.^2-a^2.*z.^4+3*d^2.*z.^4-3.*x.^2.*z.^4-z.^6)<= 0;
The following step is use:
[X,Y,Z] = meshgrid(x,y,z);
but the usage the memory is so large (+70 gb).
Is there another way to create geometry and meshing for this region?
1 Kommentar
Image Analyst
am 17 Jan. 2020
Bearbeitet: Image Analyst
am 17 Jan. 2020
Not sure what you're looking for. I'm not sure what a "a tetrahedron or Hexahedron mesh" is. Do you have some kind of picture of it that you can post? Some guesses:
Antworten (0)
Siehe auch
Kategorien
Mehr zu Surface and Mesh Plots finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!