Question about sprintf function.
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Here's my syntax:
bm= input ('value');
val = 43 ;
A = sprintf('%d',val);
%if i declare A(1), ans is 4, which is correct.
c=0;
A1 = A(1) .* (bm^(c))
Why is it that if my bm = 8, A1 = 52? its like 4 * 8 = 52. i think my error here is the sprintf function.
0 Kommentare
Akzeptierte Antwort
Image Analyst
am 29 Sep. 2012
Why not just do
A1 = val;
???? bm^c is just 1, and I'm not sure if you really wanted to take the first digit of 43. If you did, you could just do
A1 = floor(A/10); % As long as A is less than 100.
instead of using sprintf. Is A really some sort of ASCII or hexadecimal number?
6 Kommentare
Image Analyst
am 29 Sep. 2012
Yes, you're right. It does really only go to 16. I didn't have a "clearvars" or "clear all" in there so there was left over stuff in theNumbers from prior test runs. This shows one good reason to use clear (though I know Jan doesn't like it) is to avoid goofs like this. Sorry about that.
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Discrete Math finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!