HOW TO APPLY A MEAN FILTER FOR 3x3

I NEED TO APPLY THE 3x3 MEAN FILTER TO THE GRAY SCALE IMAGE. PLS SEND ME THE CODE FOR THAT

 Akzeptierte Antwort

Wayne King
Wayne King am 27 Sep. 2012

1 Stimme

How about just:
h = 1/3*ones(3,1);
H = h*h';
% im be your image
imfilt = filter2(H,im);

6 Kommentare

ajith
ajith am 27 Sep. 2012
Bearbeitet: ajith am 27 Sep. 2012
GREAT SIR THANKS A LOT
suadad najim
suadad najim am 9 Feb. 2023
Can you tell me about the meaning of (ones) in your code please?
h = 1/3*ones(3,1);
H = h*h';
H
H = 3×3
0.1111 0.1111 0.1111 0.1111 0.1111 0.1111 0.1111 0.1111 0.1111
Notice this is the same as
ones(3,3)/9
ans = 3×3
0.1111 0.1111 0.1111 0.1111 0.1111 0.1111 0.1111 0.1111 0.1111
which in turn is the same as
[1/9, 1/9, 1/9;
1/9, 1/9, 1/9;
1/9, 1/9, 1/9]
ans = 3×3
0.1111 0.1111 0.1111 0.1111 0.1111 0.1111 0.1111 0.1111 0.1111
The ones() that @Wayne King used is a shorter way of writing out the individual components of the matrix.
See Image Analyst's discussion below https://www.mathworks.com/matlabcentral/answers/49226-how-to-apply-a-mean-filter-for-3x3#comment_2060839 about why you need to divide by 9 in this context.
suadad najim
suadad najim am 10 Feb. 2023
@Walter Roberson Thank you for quick answer
I want you to see the image before and after applying the mean filter you gave. Is that normal?
Orginal image Resulted image
Walter Roberson
Walter Roberson am 10 Feb. 2023
Check class() of the input image and class() of the output image. I suspect that class of the output is double and that you would get what you want if you uint8() that.
What is the class and scale of the input and output? The rendering of an image depends on an assumption of where white and black are. Floating-point images are expected to be unit-scale (i.e. 0-1). If you're using the above code, then it will be uint8-scale (0-255)
% this is a uint8 image
im = imread('cameraman.tif');
% create filter
h = 1/3*ones(3,1);
H = h*h';
% the output of this will be class 'double', but scaled as if uint8
imfilt = filter2(H,im);
% cast it to a class appropriate for its scale
imfilt = uint8(imfilt);
% display it
imshow(imfilt)
See also:

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Weitere Antworten (5)

Image Analyst
Image Analyst am 27 Sep. 2012

3 Stimmen

filteredImage = conv2(single(grayscaleImage), ones(3)/9);

7 Kommentare

filteredImage = conv2(grayscaleImage, ones(3)/9,'same');
Image Analyst
Image Analyst am 10 Aug. 2016
This will work if your grayscaleImage is already converted to double or single. Also, there are 3 edge options: 'same', 'full' (the default if none is supplied), and 'valid'. Usually for image processing the 'same' option is used.
Atalay Asa
Atalay Asa am 7 Jun. 2020
How can we use it for 7x7 arithmetic mean filter?
windowWidth = 7;
kernel = ones(windowWidth) / windowWidth^2;
outputImage = imfilter(grayImage, kernel);
SP
SP am 7 Jun. 2021
Hello, Sir. Can you explain to me that why the value in neighborhood need to be 1/9 (or 0.111)?
Ridho Liwardana
Ridho Liwardana am 23 Mär. 2022
It's depend of matrix that you wanna use as filter, if it's a 3x3 matrix, the value is 1/(3x3) -> 1/9.
@SP The reason you divide by windowWidth^2 (1/9 in this case) is because if you don't, the filtering is the sum of the filter window times the image to be filtered. So if the image were all 255 under the filter, you'd get an output value of 9*255 instead of 255. So the image would be 9 times as bright. To ensure that the filtered image lies in the same intensity range as the original image, you need to divide the filter values by windowWidth^2.
If you didn't have a uniform filter (like here where they are all 1's) you'd have to divide by the sum of the kernel:
% Divide unnormalized kernel by the sum of the values in it.
% This will ensure the output image has the same intensity range as the original.
kernel = kernel / sum(kernel(:));
outputImage = imfilter(grayImage, kernel);
Actually, that is the most general approach which will work for any filter.

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Mohamed Batran
Mohamed Batran am 11 Jul. 2015

0 Stimmen

thank you for your reply simple but helped a lot for customizing the filter i want
Geetha raja
Geetha raja am 19 Aug. 2018

0 Stimmen

I NEED TO APPLY THE bilateral FILTER TO THE GRAY SCALE IMAGE for denoising. PLS SEND ME THE CODE FOR THAT

1 Kommentar

Image Analyst
Image Analyst am 19 Aug. 2018
Geetha, there is a part of the web site called "File Exchange". You can look there for community-contributed programs: Search for bilateral filter

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Jahid Hasan
Jahid Hasan am 19 Apr. 2022

0 Stimmen

Sorry to ask here, how to write mean and median filter without using a in-built function? What are the way to do it? Any help or code syntax. Thank you

4 Kommentare

Image Analyst
Image Analyst am 19 Apr. 2022
You'd use a for loop in the obvious way where you just sum the elements and divide by the number of elements.
For median you'd need to write your own sorting routine (see Wikipedia or somewhere) and then take the middle element.
Jahid Hasan
Jahid Hasan am 19 Apr. 2022
Thanks for your reply. Do you have any examples of it as a reference to understand it.
Potential reference implementation. Not tested.
sum_of_elements = 0;
index_of_element = 0;
while true
index_of_element = index_of_element + 1;
try
sum_of_elements = sum_of_elements + YourVector(index_of_element);
catch ME
break; %we ran off the end of the array
end
end
number_of_elements = index_of_element - 1; %loop over-counts by 1
mean_of_YourVector = sum_of_elements ./ number_of_elements;
sorted_vector = bogosort(YourVector, number_of_elements);
index_of_element = 0;
while true
index_of_element = index_of_element + 1;
if index_of_element + index_of_element == number_of_elements
median_of_YourVector = YourVector(index_of_element);
break
elseif index_of_element + index_of_element + 1 == number_of_elements
median_of_YourVector = (YourVector(index_of_element) + YourVector(index_of_element+1)) / 2;
break
end
end
function sortedVector = bogosort(vectorToSort, number_of_elements)
%this is a legitimate sort
while true
neworder = randperm(number_of_elements);
sortedVector = vectorToSort(neworder);
index_of_element = 0;
while true
index_of_element = index_of_element + 1;
if index_of_element >= number_of_elements
%we got to the end of the list without detecting out-of-order
return;
end
if YourVector(index_of_element) > YourVector(index_of_element+1)
%detected something out of order, try again with a new order
break
end
end
end
end

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Gefragt:

am 27 Sep. 2012

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DGM
am 10 Feb. 2023

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