# Export colors of hist3 boxes in an array

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MichailM am 18 Nov. 2019
Bearbeitet: Adam Danz am 19 Nov. 2019
Having the simple script below:
close all;
clear all;
clc;
x = rand(10,2);
hist3(x,'CdataMode','auto')
view(2)
which generates a figure like the one below,
Is there any way I can possibly export the RGB colors in a NxNx3 array (here N=10)?
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### Akzeptierte Antwort

Adam Danz am 18 Nov. 2019
Bearbeitet: Adam Danz am 19 Nov. 2019
After creating the bivariate histrogram with hist3(), call the function again with the same inputs but this time, store the first output which is the binvariate bin count N = hist3(___). This will not produce a plot which is why it must be called separately from the plot.
Assuming the bivariate histrogram was produced with default CDataMapping property, you can scale the bin counts to the axes colormap range to compute the RGB values for each bin.
% Produce the bivariate hist
x = rand(10,2);
hist3(x,'CdataMode','auto') % produces plot
count = hist3(x); % grabs bin count; does not produce plot
view(2)
ax = gca(); % Get axis handle
cm = ax.Colormap; % Get axis colormap
%Scale the bin count to colormap scale
count = round((count-min(count(:)))./max(count(:)).*(size(cm,1)-1) + 1);
% produce 3D array with 3 'pages' for RGB values
% This has the same orientation as 'count'
rgbArray = permute(reshape(cm(count,:).', [3,size(count)]),[2,3,1]);
Investigate the count matrix to explore the mapping between the count bins and your histrogram bins. You'll find that the first column of count represents the bottom row of bins in the plot. Therefore rgbArray(i,j,:) contains the color for the i-th column and j-th row from the bottom. You may want to do some transposing or flipping to orient the array to your liking.
hist3() produces a surface object. Check out more surface properties here:
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Adam Danz am 19 Nov. 2019
Bearbeitet: Adam Danz am 19 Nov. 2019
ahh.... a simple fix is to round the count variable. I updated my answer to reflect that change.
% old line
count = (count-min(count(:)))./max(count(:)).*(size(cm,1)-1) + 1;
% New line
count = round((count-min(count(:)))./max(count(:)).*(size(cm,1)-1) + 1);
% ^^^^^^ ^

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