Creating a tridiagonal matrix

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Aaron Atkinson
Aaron Atkinson am 11 Nov. 2019
Kommentiert: Ana Sarai am 22 Feb. 2025
I am currently trying to create a 500*500 matrix in matlab with diagonals a=-1, b=4, c=2. My teacher has said that the best way to go about it is using loops, but is there a coded in function to use?
  2 Kommentare
David Goodmanson
David Goodmanson am 11 Nov. 2019
Hi Aaron
check out the 'diag' function
Alex Treat
Alex Treat am 30 Okt. 2020
coughs you were in the mec 103 class at CSU...

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Stephen23
Stephen23 am 11 Nov. 2019
Bearbeitet: Stephen23 am 20 Mär. 2022
"My teacher has said that the best way to go about it is using loops"
Why on earth would they say that? Here are some non-loop aproaches:
2- Use diag :
>> N = 10;
>> a = -1;
>> b = 4;
>> c = 2;
>> M = diag(a*ones(1,N)) + diag(b*ones(1,N-1),1) + diag(c*ones(1,N-1),-1)
M =
-1 4 0 0 0 0 0 0 0 0
2 -1 4 0 0 0 0 0 0 0
0 2 -1 4 0 0 0 0 0 0
0 0 2 -1 4 0 0 0 0 0
0 0 0 2 -1 4 0 0 0 0
0 0 0 0 2 -1 4 0 0 0
0 0 0 0 0 2 -1 4 0 0
0 0 0 0 0 0 2 -1 4 0
0 0 0 0 0 0 0 2 -1 4
0 0 0 0 0 0 0 0 2 -1
3- indexing is reasonably simple:
>> M = zeros(N,N);
>> M( 1:1+N:N*N) = a;
>> M(N+1:1+N:N*N) = b;
>> M( 2:1+N:N*N-N) = c
M =
-1 4 0 0 0 0 0 0 0 0
2 -1 4 0 0 0 0 0 0 0
0 2 -1 4 0 0 0 0 0 0
0 0 2 -1 4 0 0 0 0 0
0 0 0 2 -1 4 0 0 0 0
0 0 0 0 2 -1 4 0 0 0
0 0 0 0 0 2 -1 4 0 0
0 0 0 0 0 0 2 -1 4 0
0 0 0 0 0 0 0 2 -1 4
0 0 0 0 0 0 0 0 2 -1
  7 Kommentare
Stephen23
Stephen23 am 30 Okt. 2020
"It's not clear to me how you're indexing a matrix using just one argument."
The second example uses linear indexing:
Ana Sarai
Ana Sarai am 22 Feb. 2025
Thank you, = )

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