if statement in for loop with cell arrays

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nazlihan okcuer
nazlihan okcuer am 29 Okt. 2019
Bearbeitet: Guillaume am 30 Okt. 2019
I have this problem with matlab, I have to assign letter grades to the scores I have, but I couldn't do it. Can anybody help?
s.name={'Seda','Ayça','Deniz','Kerem','Mete'}
s.score={'90','45','68','86','82'}
N=lenght(s.score)
for i = 1:1:N
if (i)<100 & (i)>=90
grades(i)='A'
elseif (i)<90 & (i)>=80
grades(i) ='B'
elseif (i)<80 & (i)>=70
grades ='C'
elseif (i)<70 & (i)>=60
grades ='D'
else
grades = 'F'
end
end
  5 Kommentare
Fabio Freschi
Fabio Freschi am 29 Okt. 2019
Can you have char varaible as values in discretize?
Guillaume
Guillaume am 30 Okt. 2019
Bearbeitet: Guillaume am 30 Okt. 2019
Can you have char varaible as values in discretize?
Yes,
>> score = [90, 45, 68, 86, 82];
>> discretize(score, [0 60 70 80 90 100], {'F', 'D', 'C', 'B', 'A'})
ans =
1×5 cell array
{'A'} {'F'} {'D'} {'B'} {'B'}
All discretize does is index the values array with the indices it would normally return. You can have pretty much anything that can be indexed as values.

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Antworten (1)

Fabio Freschi
Fabio Freschi am 29 Okt. 2019
To stick with the OP snippet
  1. I added semicolons all over the place
  2. I changed the variable type in s.score to doubles
  3. I preallocated the grades variable as string array
  4. I changed the check on (i) with s.score{i}
  5. I added <= 100 to include also the possibility of 100 score
  6. I changed the single & to double && for logical scalar values
s.name={'Seda','Ayça','Deniz','Kerem','Mete'};
s.score={90,45,68,86,82};
N=length(s.score);
grades = strings(N,1);
for i = 1:1:N
if s.score{i}<=100 && s.score{i}>=90
grades(i)='A';
elseif s.score{i}<90 && s.score{i}>=80
grades(i) ='B';
elseif s.score{i}<80 && s.score{i}>=70
grades(i) ='C';
elseif s.score{i}<70 && s.score{i}>=60
grades(i) ='D';
else
grades(i) = 'F';
end
end

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