Why is this not outputting anything?

1 Ansicht (letzte 30 Tage)
Hunter Steele
Hunter Steele am 9 Okt. 2019
Bearbeitet: Adam Danz am 9 Okt. 2019
function output = MyMin(x)
MIN_VALUE=0;
[m, n]=size(x);
for i=1:length(x)
if MIN_VALUE>x(i)
MIN_VALUE=x(i);
index=i;
output = [MIN_VALUE, index];
end
end

Akzeptierte Antwort

meghannmarie
meghannmarie am 9 Okt. 2019
Bearbeitet: meghannmarie am 9 Okt. 2019
For this to work you need to set your intial MIN_VALUE to inf rather than 0. If its set to zero, it will only make output if you send it a negative number, otherwise it will never go into that if statement.
function output = MyMin(x)
MIN_VALUE=inf;
for i=1:length(x)
if MIN_VALUE>x(i)
MIN_VALUE=x(i);
index=i;
output = [MIN_VALUE, index];
end
end
end
  2 Kommentare
Hunter Steele
Hunter Steele am 9 Okt. 2019
Thank you for making that clear!
Adam Danz
Adam Danz am 9 Okt. 2019
Bearbeitet: Adam Danz am 9 Okt. 2019
I didn't see meghannmarie's answer, before posting mine (minutes apart). I just wanted to add that the min() function does what you're loop is doing and it's a lot more efficient.
[MIN_VALUE, index] = min(x);
The only difference is that the min() function splits the output into two while yours reutrns a 1x2 vector.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by