Hi,
I am wonderinh whether I can write something like this:
If any(ismember(result , [" nafor", "kform", "acet"]))

 Akzeptierte Antwort

meghannmarie
meghannmarie am 3 Okt. 2019
Bearbeitet: meghannmarie am 3 Okt. 2019

0 Stimmen

if you are trying to match string to string, try this:
if any(contains([' nafor','kform','acet'],result))

5 Kommentare

Muazma Ali
Muazma Ali am 3 Okt. 2019
as I have written I am dealing with string vectors here, not single string.
The vector may contain one of the mentioned strings that the if statement has to investigate
meghannmarie
meghannmarie am 3 Okt. 2019
Bearbeitet: meghannmarie am 3 Okt. 2019
Maybe I do not undertsand your question, this gives me a true answer for your if statement to investigate.
result = ["kform","acet","other"];
if any(contains({' nafor','kform','acet'},result))
...
end
Muazma Ali
Muazma Ali am 3 Okt. 2019
Thanks I understand it now.
Stephen23
Stephen23 am 4 Okt. 2019
Bearbeitet: Stephen23 am 4 Okt. 2019
Note that [] is a concatenation operator, so this code:
[' nafor','kform','acet']
is just a complex way of writing this:
' naforkformacet'
Perhaps you actually intended to define strings, rather than character vectors?
Muazma Ali
Muazma Ali am 4 Okt. 2019
No i was thinking of character vectors and I got my answer yesterday that I accepted :)

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Characters and Strings finden Sie in Hilfe-Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by