putting the combinations of a sequence in an cell array

AllCombinations = {1 2 3 4 5 [1 2] [1 3] [1 4] [1 5] [2 3] [2 4] [2 5] [3 4] [3 5] [4 5] [1 2 3] [1 2 4] [1 2 5] [1 3 4] [1 3 5] [1 4 5] [2 3 4] [2 3 5] [2 4 5] [3 4 5] [1 2 3 4] [1 2 3 5] [1 2 4 5] [1 3 4 5] [2 3 4 5] [1 2 3 4 5] }
A =[num2cell(combnk(1:5, 1),2)' [num2cell(combnk(1:5, 2),2)'[num2cell(combnk(1:5, 3),2)'[num2cell(combnk(1:5, 4),2)'[num2cell(combnk(1:5, 5),2)'] 

Goal:

AllCombinations = {1 2 3 4 5 [1 2] [1 3] [1 4] [1 5] [2 3] [2 4] [2 5] [3 4] [3 5] [4 5] [1 2 3] [1 2 4] [1 2 5] [1 3 4] [1 3 5] [1 4 5] [2 3 4] [2 3 5] [2 4 5] [3 4 5] [1 2 3 4] [1 2 3 5] [1 2 4 5] [1 3 4 5] [2 3 4 5] [1 2 3 4 5] }

generate a cell array which is similair to this, but without entering the values manually

I have a set [1 2 3 4 5] and I have to generate all possible combinations and put it in a cell array, such that comk{6} returns [1 2]. Hence order is also important.

I personally thought about using a loop to get something like this, but i am not sure how the loop should be constructed.

A =[num2cell(combnk(1:5, 1),2)' ..... [num2cell(combnk(1:5, 5),2)'] 

Answer 1

[Stephen23]

>> vec = 1:5;
>> fun = @(n)num2cell(combnk(vec,n),2);
>> out = arrayfun(fun,1:numel(vec),'uniformoutput',0);
>> out = vertcat(out{:});
>> out{:}
ans =
     1
ans =
     2
ans =
     3
ans =
     4
ans =
     5
ans =
     1     2
ans =
     1     3
ans =
     1     4
ans =
     1     5
ans =
     2     3
ans =
     2     4
ans =
     2     5
ans =
     3     4
ans =
     3     5
ans =
     4     5
ans =
     1     2     3
ans =
     1     2     4
ans =
     1     2     5
ans =
     1     3     4
ans =
     1     3     5
ans =
     1     4     5
ans =
     2     3     4
ans =
     2     3     5
ans =
     2     4     5
ans =
     3     4     5
ans =
     1     2     3     4
ans =
     1     2     3     5
ans =
     1     2     4     5
ans =
     1     3     4     5
ans =
     2     3     4     5
ans =
     1     2     3     4     5
>>