a=[1
4,5
7 ]
(1*3 matrix)
B=[1
10
12,14]
(1*3 matrix)
i have a print the max of a and b??

6 Kommentare

James Tursa
James Tursa am 21 Sep. 2019
Please clarify what you really have and what you want as a result, because what you have written isn't valid MATLAB syntax.
dinesh kumar mohan
dinesh kumar mohan am 21 Sep. 2019
To be clear.. I have an excel file, in which I have activities A, B, C, D in first column.. in second column I have duration for each activity as 3,4,5,6.. 3rd column which says each activity depend on other activities for example activity C depends on A,B.. I have to print the result for C as maximum of duration of A and B.. I have 50-60 activities..
dinesh kumar mohan
dinesh kumar mohan am 21 Sep. 2019
So for activity C. Result will be 4 because 4 of activity B is higher than activity A
madhan ravi
madhan ravi am 21 Sep. 2019
Why not upload the file?
dinesh kumar mohan
dinesh kumar mohan am 21 Sep. 2019
from the attchemendt i have to read theexcel and find the critical path and start and finish of each activity.
Guillaume
Guillaume am 21 Sep. 2019
How is what you're now asking in any way related to your original question?

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Antworten (1)

Dheeraj Singh
Dheeraj Singh am 3 Okt. 2019

0 Stimmen

You can try the following approach:
First you can make cell for all processes and populate it with duration of all processes it depends on.
The cell array may look like:
s=cell(7,1);
s{1}=[];%duration 2
s{2}=[];%duration 1
s{3}=[];%duration 3
s{4}=[2 1];%depends on 1 and 2
s{5}=[1 3];%depends on 2 and 3
s{6}=[3];%depends on 3
s{7}=[s{4} s{5} s{6}]%depends on 4,5,6
After getting all the duration populated, we can get the maximum for each column in the following manner:
t=cellfun(@max,s,'UniformOutput',false)
The empty cells mean the process is not dependent on any other process.

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am 3 Okt. 2019

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