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array: concatenate two columns of integers to one colum

(Matlab novice)
I thought this would be so easy...
I have a 2-d array of integers and I want to combine two columns like this:
... 123 456 ...
... 123 456 ...
etc...
I want:
... 123456 ...
... 123456 ...
etc...
as single numbers (that is, I want (123 * 1000) + (456)
The number of rows will be variable from one run to the next.
Any help would be appreciated.

  1 Comment

The question is not clear. What is the wanted output for: [1,2,3,4; 5,6,7,8; 9,10,11,12] ?

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5 Answers

Answer by Honglei Chen
on 13 Sep 2012
Edited by Honglei Chen
on 13 Sep 2012
 Accepted Answer

a = randi([1 100],[5 4]) % a 5x4 integer matrix
b = cellfun(@num2str,{a(:,2:3)},'UniformOutput',false)
c = cellfun(@(x) strrep(x,' ',''), cellstr(b{1}),'UniformOutput',false)
a(:,2) = str2double(c)
a(:,3) = []

  2 Comments

Faster:
b = sprintf('%d%d*', a(:, 2:3).');
c = sscanf(b, '%d*'); [EDITED, thanks Honglei]
STRREP operates on cell string directly, so there is usually no need to create a time-consuming anonymous function inside CELLFUN.
@Jan, thanks for the tip. That's a good one. I think you missed a b in your second expression.

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Answer by Tom
on 13 Sep 2012
Edited by Tom
on 13 Sep 2012

A=[1 2 3;3 5 7];
B=[7 8 9;4 5 6];
%
C=[A B];
w=size(C,2);
D=10.^(w-1:-1:0);
Out=sum(bsxfun(@times,D,[A B]),2)

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Answer by Jan
on 13 Sep 2012
Edited by Jan
on 13 Sep 2012

A = [1234, 567; 1, 234];
B = A(:, 1) .* nextpow10(A(:, 2)) + A(:, 2);
function Y = nextpow10(X)
Y = 10 .^ floor(log10(abs(n)) + 1); % [EDITED]
Please test this before using, I cannot run Matlab currently.

  1 Comment

A=randi(67,6,4)
n = ceil(log10(A(:,2:end)));
out = sum(A(:,1:end-1).*(10.^fliplr(cumsum(fliplr(n),2))),2)+ A(:,end)

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Answer by William Sampson on 13 Sep 2012

Yeah - so
1) I'm not getting it and
2) I seem to not have been clear enough (sorry...)
what I have is a data array with 59 columns and an indeterminate number of rows and I want to combine 2 (for example) columns as described above. In reality it is 5 columns, 8 - 12, of 16 digits each, but I'll start with getting 2 of them done.
So I have, e.g., rawData(:,9) and rawData(:,10) to combine

  2 Comments

It's the same. I updated my answer to show an example of combining 2nd and 3rd column of a matrix
See my suggestion:
B = rawData(:, 9) .* nextpow10(rawData(:, 10)) + rawData(:, 10)
result = [rawData(:, 1:8), B, rawData(:, 11:end)]
I do not see, why the suggested method should not work.
Btw. What do you expect as result of two 16 digit numbers? You can store only 16 digits in variables of the type DOUBLE.

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Answer by Ryan
on 13 Sep 2012
Edited by Ryan
on 13 Sep 2012

A = [1234, 567; 1, 234]; %Sample Data
% Figure out how many spaces to shift the left column
C = ceil(log10(A(:,2)));
% Find areas where the value is a multiple of 10 or is 1
idx = A(:,2) == 1 | rem(A(:,2),10) == 0;
C(idx) = C(idx) + 1; % Handle the exception
% Determine how much to shift the left column
C = 10.^C;
% Add in the right column
A = A(:,1).*C + A(:,2);

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