Calculating maximum distance from 3 different points
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
So I generate a test array and three points (Q) using command window:
pixels = zeros(1,3,3,'uint8');
pixels(:,:,1) = [54,50,45];
pixels(:,:,2) = [48,52,43];
pixels(:,:,3) = [50,41,47];
Q1 = [54,48,50];
Q2 = [50,52,41];
Q3 = [45,43,47];
I use my first function which calculates the median of pixels and this is put into an array e.g P=[54,55,76].
I use my second function to calculate the distance between pixels, which is:
[squaredDistance] = PixelDistance(P,Q)
However, I need to subtract Q1 from P as well as Q2 from P and Q3 from P using squared distance formula e.g
P=[54,55,76]
Q1 = [54,48,50]
[squaredDistance] = PixelDistance(P,Q1)
The question is how do I subtract Q1,Q2, and Q3 given that the function only works with Q?
2 Kommentare
Image Analyst
am 8 Sep. 2019
How is 76 in P the median of any subset of numbers in pixels? It's outside the range of any of them. Also, why are you using a 3-D array for pixels (one row by 3 columns by 3 planes) instead of a normal 3 rows-by-3 columns matrix?
I don't know what PixelDistance() does, but to have it operate on all 3 Q, just pass in all three Q one at a time:
[squaredDistance1] = PixelDistance(P,Q1)
[squaredDistance2] = PixelDistance(P,Q2)
[squaredDistance3] = PixelDistance(P,Q3)
Antworten (1)
Jyotish Kumar
am 12 Nov. 2019
Bearbeitet: Jyotish Kumar
am 12 Nov. 2019
Hi,
If the code is vectorizable, PixelDistance(P, [Q1;Q2;Q3]) should give the desired output.
If not, to achieve a shorter way to compute the distances w.r.t all Qs at once, the code needs to be vectorized.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Feature Detection and Extraction finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!