I think I will simply iterate through the rectangles and add all 4 of their points to the result matrix, then select unique rows from the result. If you have a more efficient solution, let me know
Best way to create a matrix of points?
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Richárd Tóth
am 5 Sep. 2019
Kommentiert: Bruno Luong
am 5 Sep. 2019
Hello
I have a matrix that contains rectangles(squares in this case), for example:
A=[-5 -4.5 1.5 2; -5 -4.5 2 2.5; -5 -4.5 2.5 3; -4.5 -4 1.5 2; -4.5 -4 2 2.5; -4.5 -4 2.5 3];
for i=1:6
rectangle('Position',[A(i,1) A(i,3) 0.5 0.5]);
hold on;
end
hold on;
axis([-10 10 -10 10])
Each row contains ( ) coordinates.
So in this case the result matrix should contain 12 rows, each represents 1 point, like:
-5 1.5
-5 2
-5 2.5
-5 3
-4.5 1.5
-4.5 2
-4.5 2.5
-4.5 3
-4 1.5
-4 2
-4 2.5
-4 3
The rectangles are not guranteed to form another rectangle, a more realistic set of rectangles:
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Akzeptierte Antwort
Guillaume
am 5 Sep. 2019
Bearbeitet: Guillaume
am 5 Sep. 2019
A=[-5 -4.5 1.5 2; -5 -4.5 2 2.5; -5 -4.5 2.5 3; -4.5 -4 1.5 2; -4.5 -4 2 2.5; -4.5 -4 2.5 3];
points = unique([A(:, [1, 3]); A(:, [1, 4]); A(:, [2, 3]); A(:, [2, 4])], 'rows')
is the simplest though posibly not the most efficient.
edit: this may be marginally more efficient, though more obscure:
points = unique(reshape(A(:, [1 1 2 2 3 4 3 4])), 'rows')
3 Kommentare
Guillaume
am 5 Sep. 2019
Oops! How did that happen, should have been:
points = unique(reshape(A(:, [1 1 2 2 3 4 3 4]), [], 2), 'rows')
Bruno Luong
am 5 Sep. 2019
I don't know how A is generated but you might cautious to replace UNIQUE with UNIQUETOL in case two adjacent rectangles do not have the exact match of coordinates due to round-off.
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