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Solve systems of linear equations Ax = B for x

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Johan Johan
Johan Johan am 29 Aug. 2019
Bearbeitet: Stephen23 am 29 Aug. 2019
x = A\B solves the system of linear equations A*x = B. The matrices A and B must have the same number of rows.
But ,what is the operation between the rows?
There is any one can solve this example–manually ?
A =
1 3
4 2
b= [6 ;7];
>> A\b
ans =
0.9000
1.7000
How to find 0.9 and 1.7 exactly?

Akzeptierte Antwort

Stephen23
Stephen23 am 29 Aug. 2019
Bearbeitet: Stephen23 am 29 Aug. 2019
"But ,what is the operation between the rows?"
Both mldivide and mrdivide can use many different algorithms for solving systems of linear equations, as documented in the mldivide documentation. There is no single "operation" that describes all of those algorithms.
"There is any one can solve this example–manually ?"
This is easy using standard definitions for solving linear equations, e.g. elimination of variables:
System definition:
First solve the first equation for x:
Second, substitute x back into the second equation:
Third, solve that for y:
And finally try them with your example values:
>> A = [1,3;4,2]
A =
1 3
4 2
>> b = [6;7]
b =
6
7
>> A\b
ans =
0.9
1.7
>> y = (A(1,1)*b(2)-A(2,1)*b(1)) ./ (A(1,1)*A(2,2)-A(2,1)*A(1,2))
y =
1.7
>> x = (b(1)-A(1,2)*y) ./ A(1,1)
x =
0.9

Weitere Antworten (2)

KALYAN ACHARJYA
KALYAN ACHARJYA am 29 Aug. 2019
Bearbeitet: KALYAN ACHARJYA am 29 Aug. 2019
ans =
0.9000
1.7000
How to find 0.9 and 1.7 exactly??
format shortg;
A =[1 3
4 2];
b= [6 ;7];
A\b
Result:
ans =
0.9
1.7

Torsten
Torsten am 29 Aug. 2019
https://en.wikipedia.org/wiki/Cramer%27s_rule

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