Hi, I have
Z1= sqrt(3) * exp((pi*i)/4)
Z2= 2 * exp((pi*i)/6)
Z3= sqrt(3) * exp((3*pi*i)/4)
Z4= 2 * exp(pi*i)
Z5= 2 * exp(-pi*i)
And I would like something like
Real Complex
Z1 1.2247 + 1.2247i
Z2 1.7321 + 1.0000i
Z3 -1.2247 + 1.2247i
Z4 -2.0000 + 0.0000i
Z5 -2.0000 - 0.0000i
Using fprintf, I would think...
Thanks for your help!

 Akzeptierte Antwort

KALYAN ACHARJYA
KALYAN ACHARJYA am 27 Aug. 2019
Bearbeitet: KALYAN ACHARJYA am 27 Aug. 2019

1 Stimme

One Way:
Z1= sqrt(3) * exp((pi*i)/4)
fprintf('%f + %fi',real(Z1),imag(Z1))
More:
Z1= sqrt(3) * exp((pi*i)/4);
Z2= 2 * exp((pi*i)/6);
Z3= sqrt(3) * exp((3*pi*i)/4);
Z4= 2 * exp(pi*i);
Z5= 2 * exp(-pi*i);
disp(' Real Complex')
fprintf('\nZ1 %.4f + %.4fi',real(Z1),imag(Z1));
fprintf('\nZ2 %.4f + %.4fi',real(Z2),imag(Z2));
fprintf('\nZ3 %.4f + %.4fi',real(Z3),imag(Z3));
fprintf('\nZ4 %.4f + %.4fi',real(Z4),imag(Z4));
fprintf('\nZ5 %.4f + %.4fi',real(Z5),imag(Z5));
Result:
678.png

2 Kommentare

Savannah Roemer
Savannah Roemer am 27 Aug. 2019
You're the real MVP!
Thanks so much!
S
KALYAN ACHARJYA
KALYAN ACHARJYA am 27 Aug. 2019
No Savannah, those MPVs are my Guru here.. continually they are teaching me .
Specially @Walter Roberson, @Image Analyst @Madhan @Jan .and...many more....
Anyway thanks for your kind words!

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Weitere Antworten (4)

Adam Danz
Adam Danz am 24 Nov. 2023
Bearbeitet: Adam Danz am 24 Nov. 2023

1 Stimme

Another alternative is to use num2str which supports conversion of complex numbers to strings.
a = -2*sqrt(-3)+5/3
a = 1.6667 - 3.4641i
num2str(a)
ans = '1.6667-3.4641i'
num2str(a, 2) % specify precision
ans = '1.7-3.5i'
You would enter this as a string in fprintf
ijstr = num2str(a,3);
fprintf('%s %s', 'Z1', ijstr)
Z1 1.67-3.46i
Note that this method may return strings in undesired formats such as,
num2str(160, 2)
ans = '1.6e+02'

5 Kommentare

p = [ 9.542130347090435e-01 + 1.371703909876786e-01i
9.542130347090435e-01 - 1.371703909876786e-01i ];
fprintf(1,'%s ',num2str(p,10));
>> 00..99554422113300334477+-00..113377117700339911ii
What went wrong here?
Les Beckham
Les Beckham am 26 Nov. 2024
Bearbeitet: Les Beckham am 26 Nov. 2024
I'm not sure I can explain exactly why it does that, other than it appears to be pulling the characters out of the output of num2str by going down the columns of the 2x25 char array.
p = [ 9.542130347090435e-01 + 1.371703909876786e-01i
9.542130347090435e-01 - 1.371703909876786e-01i ];
num2str(p, 10)
ans = 2x25 char array
'0.9542130347+0.137170391i' '0.9542130347-0.137170391i'
fprintf('%s ', num2str(p,10)); % << note that you don't need the "1," stdout (1) is the default
00..99554422113300334477+-00..113377117700339911ii
One way to get what you probably want is this
c = compose('%s', num2str(p,10))
c = 2x1 cell array
{'0.9542130347+0.137170391i'} {'0.9542130347-0.137170391i'}
fprintf('%s\n', c{:})
0.9542130347+0.137170391i 0.9542130347-0.137170391i
it appears to be pulling the characters out of the output of num2str by going down the columns of the 2x25 char array.
That is exactly what it is doing. fprintf() always follows down the columns of the first parameter, completely using up the first parameter before going on to follow down the columns of the second parameter, and so on. To put it another way: fprintf() uses linear indexing order of each parameter.
p = [ 9.542130347090435e-01 + 1.371703909876786e-01i
9.542130347090435e-01 - 1.371703909876786e-01i ];
fprintf('%s ', num2str(p,10).');
0.9542130347+0.137170391i0.9542130347-0.137170391i
Note: careful examination will show that the blank from the format is at the end of the output only. This is due to the way that char() arrays are processed.
marcel hendrix
marcel hendrix am 30 Nov. 2024
Thanks, I was on the verge of submitting a bug report...
Processing matrix arguments by column has another surprise: if one prints a matrix to a file for subsequent processing in another program, the matrix will look transposed to the post-processor. I can say from experience that this bug (in the post-processor and caused by the reverse side of the keyboard) can be very hard to find ...
Note that you can avoid the c{:} step if you pass compose a string scalar format instead of a character vector format.
p = [ 9.542130347090435e-01 + 1.371703909876786e-01i
9.542130347090435e-01 - 1.371703909876786e-01i ];
c = compose("%s", num2str(p,10))
c = 2x1 string array
"0.9542130347+0.137170391i" "0.9542130347-0.137170391i"
fprintf('%s\n', c)
0.9542130347+0.137170391i 0.9542130347-0.137170391i
And that leads to the more compact
fprintf('%s\n', compose("%s", num2str(p,10)))
0.9542130347+0.137170391i 0.9542130347-0.137170391i

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Walter Roberson
Walter Roberson am 27 Aug. 2019
Bearbeitet: Walter Roberson am 27 Aug. 2019

0 Stimmen

fprintf() always ignores imaginary components of numbers. You need to ask to output the real() and imaginary() components separately,
fprintf('%2s %7.4f %+7.4fi\n', 'Z1', real(Z1), imag(Z1))
Dean
Dean am 16 Dez. 2025

0 Stimmen

x = [
2.34 + 4.35i
6.34 + 4.32i
7.45 + 3.21i
8.45 + 9.23i
];
fprintf('%0.2f + i%0.2f\r', [real(x) imag(x)].');
2.34 + i4.35 6.34 + i4.32 7.45 + i3.21 8.45 + i9.23
Steven Lord
Steven Lord am 16 Dez. 2025

0 Stimmen

You may want to use + in the format specifier.
A = [3+4i, 5, 6-7i]
A =
3.0000 + 4.0000i 5.0000 + 0.0000i 6.0000 - 7.0000i
fprintf("%d%+di\t", [real(A); imag(A)])
3+4i 5+0i 6-7i

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