Infinite for loop getting stuck. Creating a new column containing a variable.
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nskel
am 26 Aug. 2019
Kommentiert: Andrei Bobrov
am 30 Aug. 2019
Hi, I am trying to generate a new column variable within a table which is conditional on 2 other values. The for loop I am using to generate it is getting stuck, however. It is generating the right values for me but just gets stuck and goes through the column over and over again. Any help would be appreciated:
data.signal = zeros(size(data.NAPMPMIIndex));
for indx=1:numel(data.NAPMPMIIndex)
if(data.NAPMPMIIndex(indx) > 50 & data.AboveMA(indx)> 0.5)
data.signal(indx) = 0.5
elseif(data.NAPMPMIIndex(indx) > 50 & data.AboveMA(indx)< 0.5)
data.signal(indx) = -0.5
elseif(data.NAPMPMIIndex(indx) < 50 & data.AboveMA(indx)> 0.5)
data.signal(indx) = 1
else
data.signal(indx) = -1;
end
end
10 Kommentare
Adam Danz
am 29 Aug. 2019
I ran the code in your question using the data attached to your comment above. The loop is not getting stuck nor is it repeating the same column as you described. The loop runs as it should.
To confirm that, run this version below. The the only differences are
- semicolons are used to suppress unnecessary output.
- a counter "c" is used to count each iteration of the for-loop and the count is displayed so you can visually confirm that the loop has the expected 714 iterations.
load spxpmi2
data.signal = zeros(size(data.NAPMPMIIndex));
c = 0;
for indx=1:714
c = c+1;
disp(c)
if(data.NAPMPMIIndex(indx) > 50 & data.AboveMA(indx)> 0.5)
data.signal(indx) = 0.5;
elseif(data.NAPMPMIIndex(indx) > 50 & data.AboveMA(indx)< 0.5)
data.signal(indx) = -0.5;
elseif(data.NAPMPMIIndex(indx) < 50 & data.AboveMA(indx)> 0.5)
data.signal(indx) = 1;
else
data.signal(indx) = -1;
end
end
Akzeptierte Antwort
Andrei Bobrov
am 27 Aug. 2019
kk = [data.NAPMPMIIndex > 50, data.AboveMA > .5];
g = findgroups(kk(:,1),kk(:,2));
a = [-1;1;-.5;.5];
data.signal = a(g);
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