Store results of for loop in matrix
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Tchilabalo
am 20 Aug. 2019
Kommentiert: Tchilabalo
am 20 Aug. 2019
ab=[X01(:) X02(:) a(:) m(:) b(:)];
Countcell=zeros(1, length(ab))
for i=1:length(ab)
X=[(ab(i,1)+(0:(ab(i,3)/dx):ab(i,3))*1),ab(i,2)]
Y=(ab(i,4).*X)+ab(i,5)
ncol=fix(X./CS)+1;
ncol=[ncol].';
nrow=fix(Y./CS)+1
nrow=[nrow].';
Ncell=[ncol, nrow]
Countcell=Ncell(i)
end
I am trying to store all the results of a for loop into one matrix. At each iteration, the result is an (n by 2) matrix. I cant use cell2mat because these matrices have different lengths. I have tried to pre-allocate, but without success.
0 Kommentare
Akzeptierte Antwort
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!