How to assign vectors to existing vector

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karishma koshy
karishma koshy am 7 Aug. 2019
Bearbeitet: madhan ravi am 15 Sep. 2019
Hi all
I want to assign a set of vectors in place of zero to existing vectors (ventor_2). But I always want to check the the new set of vectors (newvector_2) does not have the number that exist in previous vector (vector_1)
Vector_1 = [ 1 2 3 4]
Vector_2 = [ 2 0 4 0 6 7 ] Newvector_2 = [ 2 5 4 8 6 7]
How can I do that
Thank you
  4 Kommentare
karishma koshy
karishma koshy am 7 Aug. 2019
Yes, it should be in the chronological order
karishma koshy
karishma koshy am 7 Aug. 2019
Bearbeitet: karishma koshy am 7 Aug. 2019
@Guillaume I have got a set vectors vector_1 before vector_2. So I want to confirm that newly assigned numbers to newvector_2 are not present in vector_1. I know how to check for a single number . But how can I do it for all the numbers in the vector?

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Antworten (3)

Samatha Aleti
Samatha Aleti am 12 Aug. 2019
Without logically going to each element you can use functions like find(), intersect(), setxor() for vectorization in achieving what you need. Here is how you can do it:
vector_1 = [ 1 2 3 4];
vector_2 = [ 2 0 4 0 6 7];
% x is the vector whose elements are to be added to vector_2
x = [1 2 5 8];
xcommon = intersect(x, vector_1);
vector_3 = setxor(x,xcommon);
idxZero = find(~ vector_2);
% Truncate additional elements
vector_3(length(idxZero)+1:length(vector_3)) = [];
vector_2(idxZero) = vector_3;
For detailed information on above functions, refer the following document links:
  2 Kommentare
madhan ravi
madhan ravi am 12 Aug. 2019
Where did x come from?
Samatha Aleti
Samatha Aleti am 12 Aug. 2019
I took "x" as an example here. In your case "x" is the vector set whose elements are to be added in place of zeros of vector_2.

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madhan ravi
madhan ravi am 12 Aug. 2019
Bearbeitet: madhan ravi am 15 Sep. 2019
newvector_2=vector_2;
ix=nnz(~vector_2);
v12=[vector_1,nonzeros(vector_2).'];
u=unique(v12);
d=setdiff(1:max(v12),v12);
newvector_2(~vector_2)=[d,max(v12)+(1:ix-numel(d))]

Andrei Bobrov
Andrei Bobrov am 12 Aug. 2019
Let X - interval for input data in 'vector_2'
X = [0, 15];
x = setdiff(X(1):X(2),vector_1); % input data
newvector_2 = vector_2;
lo = vector_2 == 0;
n = sum(lo);
b = repmat(x,1,ceil(n/numel(x)));
newvector_2(lo) = b(randperm(numel(b),n));

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