Hi,
if i have a path consist of six points , and i have obstacle, what i want is to put nodes in all the path to count the minimum distance between
the obstacle and the path
example.jpg

4 Kommentare

darova
darova am 3 Aug. 2019
I showed distance with green color on the image. Am i correct? Is that all you want?
1Untitled.png
mohammed alany
mohammed alany am 3 Aug. 2019
yes, i really want this
can you send the code please
darova
darova am 3 Aug. 2019
What about pdist2()?
mohammed alany
mohammed alany am 3 Aug. 2019
the problem i wanted all the coordinate of midpoints between each two nodes

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 Akzeptierte Antwort

Image Analyst
Image Analyst am 4 Aug. 2019

0 Stimmen

What if you just take the average of the initial, known points?
x = sort(rand(9, 1));
y = sort(rand(9, 1));
plot(x, y, '.-', 'Color', [247, 148, 20]/255, 'MarkerSize', 40);
grid on;
xlabel('X');
ylabel('Y');
xAve = (x(1:end-1) + x(2:end))/2;
yAve = (y(1:end-1) + y(2:end))/2;
hold on;
plot(xAve, yAve, '.', 'Color', [206, 24, 18]/255, 'MarkerSize', 40);
legend('Original Points', 'Mid Points', 'Location', 'north');
0001 Screenshot.png

3 Kommentare

mohammed alany
mohammed alany am 4 Aug. 2019
many thanks for your reply,
but, is there any way to increase the number of Mid Points
like 10 mid pointes between each two was-points (x1,y1) and (x2,y2)
Image Analyst
Image Analyst am 4 Aug. 2019
Bearbeitet: Image Analyst am 4 Aug. 2019
You could use linspace() instead of just averaging. Try this:
x = sort(rand(9, 1));
y = sort(rand(9, 1));
% Now we have sample data and can begin.
numPoints = 2; % # points in between, not including the knot endpoints.
xAve = x(1);
yAve = y(1);
for k = 2 : length(y)
inBetweenPoints = linspace(x(k-1), x(k), numPoints + 2); % 2 more to include the knots.
xAve = [xAve, inBetweenPoints(2:end)];
inBetweenPoints = linspace(y(k-1), y(k), numPoints + 2);
yAve = [yAve, inBetweenPoints(2:end)];
end
plot(xAve, yAve, '.', 'Color', [206, 24, 18]/255, 'MarkerSize', 40);
hold on;
plot(x, y, '.-', 'Color', [247, 148, 20]/255, 'MarkerSize', 40);
grid on;
xlabel('X');
ylabel('Y');
legend('Mid Points', 'Original Points', 'Location', 'north');
0001 Screenshot.png
You could also use interparc (File Exchange), or use splines (demo attached).
mohammed alany
mohammed alany am 4 Aug. 2019
many thanks Image Analyst

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Weitere Antworten (1)

Image Analyst
Image Analyst am 3 Aug. 2019

0 Stimmen

Use bwdist().

9 Kommentare

mohammed alany
mohammed alany am 3 Aug. 2019
Many thanks for your replay,
but this is not binary images, can you show me how i can get all the mid points
between each two nodes as:
d = [1 1; 2 1; 2 2; 1 2]
midpoints = [1.25 1; 1.5 1;1.75 1; 2 1; 2 1.25; 2 1.5; 2 1.75; 2 2; 1.75 2; 1.5 2; 1.25 2; 1 2]
darova
darova am 3 Aug. 2019
I can show you.
mohammed alany
mohammed alany am 3 Aug. 2019
i hope this can help me
darova
darova am 3 Aug. 2019
What kind of nodes do you like more?
3Untitled.png
mohammed alany
mohammed alany am 3 Aug. 2019
red color is enough, can you send any help???
darova
darova am 3 Aug. 2019
You mean equal distance between nodes?
Image Analyst
Image Analyst am 3 Aug. 2019
If you don't have that image, then what do you have? A list of (x,y) coordinates of where the orange spots are?
mohammed alany
mohammed alany am 3 Aug. 2019
dear Image Analyst,
i have list of (x,y) coordinates, which is six orange spots as in figure,
i would like to finde midpoints along the path in order to calculate
the minimum distance between the all path with obstacles,
in my case if i have just 6 nodes, i will find just the distance between the orange spots and obstacles and this is dosn't mean the minimum distance between the obstacle and the path
darova
darova am 4 Aug. 2019
What about interparc()?

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