How to vectorize a for loop?

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Tony
Tony am 5 Sep. 2012
How can i make that code run faster?
data_file=importdata('Hz.txt');
xA=data_file(:,1);
yA=data_file(:,2);
zA=data_file(:,3);
[ndat,yyy]=size(xA); #ndat=540
aA=1./(xA+1); %Number of randoms Ran=10000;
X1=randi([-100,150],[1,Ran])/100;
s1=randi([-100,150],[1,Ran])/100;
s2=randi([-100,150],[1,Ran])/100;
sw=randi([50,130],[1,Ran]);
T=zeros([ndat,Ran]);
H=zeros([ndat,Ran]);
XsA=zeros([1,ndat]);
Chit=zeros([1,Ran]);
t=0:0.0000000001:0.04;
for j=1:Ran
x1=X1(j);
y1=s1(j);
y2=s2(j);
w=(sw(j));
x2=-x1-1/4*y1^2-3/2*y1*y2-1/4*y2^2;
As=x1*y1*y2*exp(-w*t)+x2;
for i=1:ndat
dA=abs(As-aA(i));
[v T(i,j)]=min(dA);
I=T(i,j);
H(i,j)=x1*y2+exp(-w*t(I))+exp(x2);
XsA(i)=(H(i,j)-yA(i)).^2 ./(zA(i).^2);
Chit(j)=sum(XsA);
end
end
end
  1 Kommentar
Jan
Jan am 6 Sep. 2012
Bearbeitet: Jan am 6 Sep. 2012
An optimization needs a look in the profiler (although this disables the important JIT!) and the possibility to run the code. Even advanced programmers cannot predict, how the JIT will handle modifications of the code. Therefore it would be helpful, if you provide test data. E.g. RAND with a fixed seed is a good and cheap method in the forum - if such data are valid for the tests.

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Akzeptierte Antwort

Jan
Jan am 6 Sep. 2012
Bearbeitet: Jan am 6 Sep. 2012
At first follow the standard rule to avoid all repeated calculations by moving them befor the loop:
c1 = exp(-w * t);
c3 = 1 ./ (zA .^ 2);
for j=1:Ran
x1 = X1(j);
y1 = s1(j);
y2 = s2(j);
w = sw(j);
x2 = -x1 - 0.25 * y1^2 - 1.5 * y1 * y2 - 0.25 * y2^2;
As = x1 * y1 * y2 * c1 + x2;
c4 = x1 * y2 + exp(x2);
for i = 1:ndat
dA = abs(As - aA(i));
[v, I] = min(dA);
T(i,j) = I;
H(i,j) = c4 + c1(I);
XsA(i) = (H(i,j) - yA(i)) .^ 2 .* c3(i);
end
Chit(j) = sum(XsA); % I guess this should be here
end
From this point a vectorizeation would mean to replace "i" inside the loop by "1:ndat".
  1 Kommentar
Tony
Tony am 6 Sep. 2012
the Chit is ok. and also c4 and c3. But w,t are vectors so c1 is not working. Also i have the same code for another problem where inside the 1:ndat loop there is a quad command. i.e. H=quad(As,0,t(I))*aA(i).

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Weitere Antworten (2)

Doug Hull
Doug Hull am 6 Sep. 2012
400 Million long vector t seems excessive to me.
What if you make it significantly shorter? I would lower your number of iterations on everything. See if that gives good results. Then start cranking up the number of iterations, and resolution. If it is not fine enough, then run it through the profiler to see where the bottlenecks are. My guess is that doing the above will get the results you need without code changes.
  1 Kommentar
Tony
Tony am 6 Sep. 2012
When i define a smaller vector t , i don't have accuracy in the dA. But if that cost, i think that will be ok if i can set 4M long t.

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Robert Cumming
Robert Cumming am 6 Sep. 2012
you over write:
Chit(j)=sum(XsA);
in every i loop - are you sure you want to do that?
Profile the code and you will see which lines are the most expensive.
  2 Kommentare
Tony
Tony am 6 Sep. 2012
I have correct that.
Jan
Jan am 6 Sep. 2012
Bearbeitet: Jan am 6 Sep. 2012
Where have you corrected this? Is sum(XsA) calculated inside or outside the for i loop?

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