Double to cell conversion.

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Dwight
Dwight am 4 Sep. 2012
I'm trying to store a string of characters in my [data_accuracy] variable (instead of storing for example 0 or 1) based on a conditional if statement. cellstr and num2str or { } based approaches have not worked and continue to give me the error: Conversion to cell from double not possible. Any suggestions? Thanks!
Example:
if data(i,1) == 1;
data_accuracy(i,1) = 'hit';
elseif data(i,1) == 2;
data_accuracy(i,1) = 'miss';
end
  1 Kommentar
Rick Rosson
Rick Rosson am 4 Sep. 2012
This approach is not a very efficient way to code an algorithm. Why do you want to have strings instead of numbers?

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Antworten (4)

Jan
Jan am 4 Sep. 2012
pool = {'hit', 'miss'};
data_accuracy = pool(data(:,1));

Azzi Abdelmalek
Azzi Abdelmalek am 4 Sep. 2012
Bearbeitet: Azzi Abdelmalek am 4 Sep. 2012
%use {} instead ()
data=randi(3,10,1) %example
for k=1:size(data,1)
if data(k,1)==1
data_accuracy{k,1} = 'hit';
elseif data(k,1) == 2;
data_accuracy{k,1} = 'miss';
end
end

Sean de Wolski
Sean de Wolski am 4 Sep. 2012
Bearbeitet: Sean de Wolski am 4 Sep. 2012
data = (rand(10,1)>0.5)+1
c = cellstr(repmat('hit',size(data)))
c(data==2) = {'miss'}

Rick Rosson
Rick Rosson am 4 Sep. 2012
Please try the following instead:
isAccurate = ( data(:,1) == 1 );
HTH.
Rick

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