Hello everyone,
I'm trying to build a stacked plot with 3 graphs using Matlab 2018b's stackedplot-function. I'd like to write the corresponding DisplayLabels in TeX-style so that I can use subscripts, as can be done in regular plots without problem using e.g.
'T_{r}'
When I create a stackedplot using below code though, the labels are printed 'as is' instead of as a subscript:
s = stackedplot(f,If,'DisplayLabels',{'T_{r} = 50 ns','T_{r} = 20 ns','T_{r} = 10 ns'});
StackedPlot.PNG
I've tried accessing Interpreter-properties and even setting
set(0,'defaultTextInterpreter','latex');
but couldn't get it to work as intended.
Can anyone please tell me how to do that?
Best regards
Sebastian

4 Kommentare

Sebastian Sprunck
Sebastian Sprunck am 29 Jul. 2019
Bumping this questions as I'm still looking for a solution.
Adam Danz
Adam Danz am 29 Jul. 2019
Bearbeitet: Adam Danz am 1 Aug. 2019
It looks like the handles to those labels aren't officially available. All you would need to do is set the "Interpreter" to "tex" which is normally the default interpreter for text but must not be the case here. Even findall() couldn't locate those handles. Maybe digging through the code will lead to an undocumented method of getting those handles but I couldn't get them otherwise.
Of course you could ditch the function and make your own subplots with identical x axes.
Sebastian Sprunck
Sebastian Sprunck am 30 Jul. 2019
Hmmm, I suspected something like that. Guess that's the curse of new functionalities ;)
Building my own subplot was my first attempt, but I'd like the x axis to only show at the bottom, as is the case in the stackedPlot variant. If I could get the labels to work as I want them, it would mean much "cleaner" code for my script.
Adam Danz
Adam Danz am 30 Jul. 2019
Bearbeitet: Adam Danz am 30 Jul. 2019
Yeah, there are a few newer plotting functions that have a bunch of features on lockdown such as heatmap() and stackedplot(). I avoid using them which is unfortunate since they have some nice added features but when you can edit the basic, they become less useful.

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 Akzeptierte Antwort

Yair Altman
Yair Altman am 31 Jul. 2019
Bearbeitet: Yair Altman am 13 Feb. 2024

4 Stimmen

You can access the individual stacked-axes' properties via the hidden sub-property Axes of the stackedplot's AxesProperties property, and then modify the YLabel's Interpreter property to 'tex' or 'latex' (it's 'none' by default).
For example, to change the middle (2nd) YLabel:
s = stackedplot(...);
drawnow % ensure that the plot is updated before proceeding
axesProps = struct(s.AxesProperties(2)); % using struct() is undocumented
axesProps.Axes.YLabel.Interpreter = 'tex';
Note that using struct() to access internal object properties is undocumented.

6 Kommentare

Adam Danz
Adam Danz am 31 Jul. 2019
+1; awesome.
Sebastian Sprunck
Sebastian Sprunck am 1 Aug. 2019
Thank you, Yair!
Ron
Ron am 3 Feb. 2024
Bearbeitet: Ron am 3 Feb. 2024
Amazing. thankyou so much sir. But I guess the developers have banned this move.
Adam Danz
Adam Danz am 4 Feb. 2024
Bearbeitet: Adam Danz am 4 Feb. 2024
This use of struct() is not banned. It still functions but throws a warning.
Ron
Ron am 4 Feb. 2024
Bearbeitet: Ron am 4 Feb. 2024
Thankyou for responsding sir but I did try but it didnt do anything except the warning.
or there is something wrong with my code??
ss=stackedplot(error,'LineWidth',1.5);
ss.DisplayLabels = [sample_name,sample_name(1)+"_{abc}"];
axesProps = struct(ss.AxesProperties(4)); % using struct() is undocumented
axesProps.Axes.YLabel.Interpreter = 'tex';
Adam Danz
Adam Danz am 13 Feb. 2024
The call to struct in this context is undocumented. It needs to be called after the stackplot is generated. This can be done by adding a drawnow before calling struct.

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