Element-wise Complex Magnitude Calculation

I have an array of complex numbers (here is a snippet):
1273 + 1513i
1271 + 1481i
1256 + 1432i
1240 + 1347i
1210 + 1183i
1190 + 1029i
1169 + 870i
1156 + 714i
I'm aware the abs() function returns the complex magnitude of the vector from the origin 0,0 for each element in the vector, however is it possible to calculate the complex magnitude in an element-wise manner such that the returned value is the absolute length of all the elements in the complex vector with each previous element being treated as the origin rather than 0,0?

3 Kommentare

Torsten
Torsten am 15 Jul. 2019
abs( z(2:n) - z(1:n-1) )
Gee
Gee am 15 Jul. 2019
Thank you so much!
or
abs(diff(z))

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Antworten (1)

Raj
Raj am 15 Jul. 2019

0 Stimmen

Why don't you just put it in a loop like this:
A = rand(5,1) + i*rand(5,1); % Assume this is your array
B=zeros(length(A),1);
B(1,1)=abs(A(1));
for ii=2: length(A)
B(ii,1)=abs(A(ii)-A(ii-1));
end
B is the matrix you need.
P.S.: There may be better way of doing this also.

2 Kommentare

Guillaume
Guillaume am 15 Jul. 2019
Bearbeitet: Guillaume am 15 Jul. 2019
"P.S.: There may be better way of doing this also."
As shown by Bruno, the whole lot can be replaced by
B = abs(diff(B);
You never need a loop to calculate the difference between consecutive elements in matlab.
Raj
Raj am 16 Jul. 2019
@Guillaume Yes i got it. Thanks. I was preoccupied in something and was not thinking straight.

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R2018b

Gefragt:

Gee
am 15 Jul. 2019

Kommentiert:

Raj
am 16 Jul. 2019

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