- each group contains exactly the same number of rows (four in your example), and
- each row contains one non-empty data value (in columns 2 - 5).
- The groups are contiguous.
How to append cell arrays with a very specific form
1 Ansicht (letzte 30 Tage)
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Piet Jonker
am 9 Jul. 2019
Kommentiert: Piet Jonker
am 11 Jul. 2019
I have a cell array looking like this
'Rating1' [] [] [] '8'
'Rating1' [] [] '3' []
'Rating1' '2' [] [] []
'Rating1' [] '2' [] []
'Rating2' '5' [] [] []
'Rating2' [] '6' [] []
'Rating2' [] [] '3' []
'Rating2' [] [] [] '7'
'Rating3' '7' [] [] []
'Rating3' [] '7' [] []
'Rating3' [] [] '3' []
'Rating3' [] [] [] '7'
with more than a hundred ratings
I want it to look likes this:
'Rating1' '2' '2' '3' '8'
'Rating2' '5' '6' '3' '7'
'Rating3' '7' '7' '3' '7'
So I have to make a new variable where it appends the score in the columns based on the string in the first column.
I can't really wrap my head around this problem. Can anybody help me perhaps, or give me a push in the right direction?
Thanks alot,
Piet (pronounce as Pete)
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Akzeptierte Antwort
Stephen23
am 9 Jul. 2019
Bearbeitet: Stephen23
am 9 Jul. 2019
As long as your data meet some assumptions:
>> C = {...
'Rating1' [] [] [] '8'
'Rating1' [] [] '3' []
'Rating1' '2' [] [] []
'Rating1' [] '4' [] []
'Rating2' '5' [] [] []
'Rating2' [] '6' [] []
'Rating2' [] [] '3' []
'Rating2' [] [] [] '7'
'Rating3' '7' [] [] []
'Rating3' [] '7' [] []
'Rating3' [] [] '3' []
'Rating3' [] [] [] '7'
};
>> D = permute(reshape(C(:,2:5),4,[],4),[1,3,2]);
>> D(cellfun('isempty',D)) = [];
>> D = [C(1:4:end,1),reshape(D,4,[]).']
D =
'Rating1' '2' '4' '3' '8'
'Rating2' '5' '6' '3' '7'
'Rating3' '7' '7' '3' '7'
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Weitere Antworten (1)
Jan
am 9 Jul. 2019
Bearbeitet: Jan
am 9 Jul. 2019
Or:
C = {...
'Rating1' [] [] [] '8'; ...
'Rating1' [] [] '3' []; ...
'Rating1' '2' [] [] []; ...
'Rating1' [] '4' [] []; ...
'Rating2' '5' [] [] []; ...
'Rating2' [] '6' [] []; ...
'Rating2' [] [] '3' []; ...
'Rating2' [] [] [] '7'; ...
'Rating3' '7' [] [] []; ...
'Rating3' [] '7' [] []; ...
'Rating3' [] [] '3' []; ...
'Rating3' [] [] [] '7'};
V = C(:, 2:5);
D = [C(1:4:end, 1), reshape(V(~cellfun('isempty', V)), [], 4)];
Or:
keep = [mod(1:size(C,1), 4).' == 1, ~cellfun('isempty', C(:, 2:5))];
D = reshape(C(keep), [], 5)
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