Find the minimum of a multi-variable function

Question: Find the minimum of in the window [0,2]×[2,4] with increment 0.01 for x and y.

My approach:

syms fun(x,y) fx(x,y) fy(x,y) fxy(x,y) x y

=;

;

;

;

pt=solve([==0,==0],[x y]) But it gives me an error.

besides what about the window and increment mentioned that question. Any solution will be appreciated .

Thanks in advance .

[infinity]

Hello,

Could you provide your code and show us what is the error?

[emonhossain roy]

code:

clc

clear all

syms fun(x,y) fx(x,y) fy(x,y) fxy(x,y) x y

fun(x,y)=x^2+y^2-2*x-6*y+14;

fx(x,y)=diff(fun(x,y),x);

fy(x,y)=diff(fun(x,y),y);

fxy(x,y)=diff(fx(x,y),y);

pt=solve([fx(x,y)==0,fy(x,y)==0],[x y])

error:

Warning: 4 equations in 2 variables.

> In C:\Program Files\MATLAB\R2013a\toolbox\symbolic\symbolic\symengine.p>symengine at 56

In mupadengine.mupadengine>mupadengine.evalin at 97

In mupadengine.mupadengine>mupadengine.feval at 150

In solve at 170

Warning: Explicit solution could not be found.

> In solve at 179

pt =

[ empty sym ]

Answer 1

[infinity]

Hello,

In your code, it was not good to put the name like "fun(x,y)". Also, we do not need to declare "fx, fun, fy,.." as symbolic variable. Here is a small code that you can refer

clear 
syms x y

fun=x^2+y^2-2*x-6*y+14;
fx=diff(fun,x);
fy=diff(fun,y);
pt=solve([fx==0,fy==0],[x y]);
% pt=solve(fx==0,fy==0);
sol = struct2array(pt)

It will give us the solution

sol =
 
[ 1, 3]

I have run this code on Matlab2018a. Maybe in your Matlab version, there will be some different.