How to plot sine graph by using for loop?
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Xing Xing
am 5 Jun. 2019
Kommentiert: AZEEM IMTIAZ
am 4 Aug. 2019
I tried to use a for loop to plot a sine graph. The values are generated but then when I try to graph them, I get either an error or no graph. Here's my code:
for i = 0:0.1:2*pi
m=sin(i);
n=i;
plot(n,m,'-r');
hold on
end
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Alex Mcaulley
am 5 Jun. 2019
You don't need a loop, just:
theta = 0:0.1:2*pi;
plot(theta,sin(theta))
6 Kommentare
AZEEM IMTIAZ
am 4 Aug. 2019
you need to define t as a continuous variable in the first line then apply for loop on the frequency as discrete values. so that each frequency point will sweep over the time that you have defined in the first line. hope this helps!
t=0:0.04:5;
hold on
for f=[0.7 1 1.5 2]
y=cos(2*pi*f*t);
plot(t,y)
end
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Mohammad Alhashash
am 5 Jun. 2019
maybe that is what you need.
t= 0:0.01:2*pi;
m =sin(t);
t_plot = NaN(1,length(t));
m_plot = NaN(1,length(m));
u = 1;
for i = 1:length(t)
cla
t_plot(i) = t(u);
m_plot(i) = m(u);
plot(t_plot,m_plot)
drawnow
u = u + 1;
end
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