How can I create a Figure Title with a variable in it?

I have a figure:
DEPTH = 10; % Depth changes based on user input
figure('Numbers at a depth of %d meters)')
How can I make my figure title update depending on my input for depth?

Antworten (1)

Adam Danz
Adam Danz am 28 Mai 2019
Bearbeitet: Adam Danz am 29 Mai 2019
DEPTH = 10; % Depth changes based on user input
title(sprintf('Numbers at a depth of %.0f meters', DEPTH))
% For the figure name (not title):
figure('Name', sprintf('Numbers at a depth of %.0f meters', DEPTH))
I prefer %.0f rather than %d to convert integers because 1) if DEPTH isn't an integer, %d will print out scientific notation and 2) if you ever want to add decimal places you can just change the 0.

Kategorien

Mehr zu Interactive Control and Callbacks finden Sie in Hilfe-Center und File Exchange

Gefragt:

am 28 Mai 2019

Bearbeitet:

am 29 Mai 2019

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by