Problem using interp1 cubic

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Alex
Alex am 21 Aug. 2012
I`m trying to inter a grapich but it`s wrong im using interp1 cubic
How should be
It looks wrong
Help.
Edit [21 Aug 2012, 12:45 BST - OK] Added Alex's answer here
x1=[ 1.0000 6.1000 10.1800 135.3000 136.5750....86.7650 83.2800]
y1=[ 1 23 40...... 2144 2152]
s=[1:0.1:95]
z=interp1(x1,y1,s,'cubic')
plot(s,z)
  6 Kommentare
Oleg Komarov
Oleg Komarov am 21 Aug. 2012
I think the problem is that it's not a function, i.e. you have multiple Ys for an X.
As Jose pointed out you might transpose the x with the y, interpolate and then re-transpose back.
Alex
Alex am 21 Aug. 2012
I try interp1(y1,x1,s,'cubic') but is the same image than jose's answer

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Antworten (2)

José-Luis
José-Luis am 21 Aug. 2012
Try inverting your x y data
interp1(x,y,...) to interp1(y,x,...)
Cheers!
  2 Kommentare
Jan
Jan am 21 Aug. 2012
Alex wrote: (Copied from Answer to the comment section:)
Don`t work
Jan
Jan am 21 Aug. 2012
Posting the problem and further explanations by picture only is not efficient. We cannot reproduce your diagrams when you do not provide the data. Perhaps only your drawing method fails?!

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Titus Edelhofer
Titus Edelhofer am 21 Aug. 2012
Hi,
the plot shows that it's not a function y = f(x) and also not a function x = g(y). So you will need to move to a 2D parametrization. Take a look at the function spline that can handle the case of an arbitrary trajectory in the plane, e.g. take a look at example 4 (the cirlce).
Titus
  3 Kommentare
Alex
Alex am 21 Aug. 2012
Bearbeitet: Alex am 21 Aug. 2012
only a part work
Alex
Alex am 21 Aug. 2012
its works i need change s=[1:0.1:95] when i transpose x and y to s=[1:0.1:2152]

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