Finding the index of spesific element in a matrix?

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IBM watson
IBM watson am 23 Mai 2019
Kommentiert: Ulika Naidoo am 22 Jan. 2021
Lets say we have matrix:
a=[ 2, 3, 5
3, 4, 7
4, 4, 4] ;
I want to know index of a(4) which is the bold 3. This is just an example. I want to learn how to find index of a(n).

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madhan ravi
madhan ravi am 23 Mai 2019
Bearbeitet: madhan ravi am 23 Mai 2019
Assuming you want to index of the last match in the matrix:
Index=find(a==3,1,'last')
  13 Kommentare
madhan ravi
madhan ravi am 23 Mai 2019
Bearbeitet: madhan ravi am 23 Mai 2019
No problem, by the way the original question you asked is totally irrelevant to your latter comment. Please don’t do this in the future riddling the answers.
Look into ind2sub() function to convert the linear indices. To understand what this statement means , you need to read the link which I shared thoroughly and practice. And finally have a look at ind2sub().
IBM watson
IBM watson am 23 Mai 2019
Sure, I didn't do it on purpose. Just could't explain clearly what I want. Thanks again.

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KALYAN ACHARJYA
KALYAN ACHARJYA am 23 Mai 2019
Bearbeitet: KALYAN ACHARJYA am 23 Mai 2019
I want to know index of a(4) which is the bold 3
here ......................... this 4^ represent the index, I guessing you are looking for following one.
idx=find(a==3);
One dimentional case array case
>> a=[2,3,5,3,4,7,4,4,4];
>> idx=find(a==7)
idx =
6
>> idx=find(a==3)
idx =
2 4
But Matrices have 2 dimention so indices represents (x,y), where answer will be little different
>> a=magic(3)
a =
8 1 6
3 5 7
4 9 2
>> [r c]=find(a==3)
r =
2
c =
1
  5 Kommentare
Stephen23
Stephen23 am 5 Mär. 2020
"why c =1 ? "
Because the value 3 is in the 1st column.

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