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Removing repeating data points but keeping the first and last ones

1 Ansicht (letzte 30 Tage)
Andrew Luce
Andrew Luce am 20 Mai 2019
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
Hello, say I have matrix with repeating parts in the frist and second row and all zeros in the third
A=1,2,3,4,5,6,7,8,9,1,1,1,1,1,1,1,1,1,3,4,5,6
9,9,9,9,9,9,9,9,9,2,3,4,5,6,7,8,9,8,2,2,2,2
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
I want to keep the columns where there is no repeating in the column before and after. Additonally, I want to keep the columns where the repeating starts and ends. The resulting matrix would look like this in the end
A=1,9,1,1,3,6
9,9,2,8,2,2
0,0,0,0,0,0
How would I get this
thank you
  2 Kommentare
Image Analyst
Image Analyst am 20 Mai 2019
What if your criteria would result in the first and second row having different numbers of elements?
Adam Danz
Adam Danz am 20 Mai 2019
I wondered that, too. For example,
A=[ 1,2,3,4,5,6,7,1,1,1,1,1,1,1,1,1,1,1,3,4,5,6;
9,9,9,9,9,9,9,9,9,9,9,4,5,6,7,8,9,8,2,2,2,2;
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0];
% ^ ^ ^ ^
Is that an example of what you were thinking, Image Analyst?
My answer removes columns in any of the rows have repeats (but keeps the first and last ones).
so,
Ap = 1 1 3 6
9 8 2 2
0 0 0 0

Antworten (1)

Adam Danz
Adam Danz am 20 Mai 2019
Bearbeitet: Adam Danz am 11 Jun. 2019
A is your input matrix, Ap is the trimmed matrix.
isUnq = find(~any(diff(A([1,2],:),[],2)==0, 1))+1;
keepColIdx = unique([1,isUnq, isUnq-1, size(A,2)]);
Ap = A(:,keepColIdx);
Result
Ap =
1 9 1 1 3 6
9 9 2 8 2 2
0 0 0 0 0 0

Produkte


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R2019a

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