Hi.
I have written an algorithm that computes an array "b" for each ith iteration [i={1,2,3,4}], and I would like to save those arrays in a structure called "A".
How to save those arrays in the structure "A" where its elements are function of "i", i.e, A = {b1, b2,b3, b4} and to get b1 for instance, one would have to type A.b1.
Regards.

2 Kommentare

Stephen23
Stephen23 am 16 Mai 2019
Bearbeitet: Stephen23 am 16 Mai 2019
Note that using a non-scalar structure would be more efficient than generating fieldnames.
Indexing is much faster and less buggy than messing around forcing meta-data (i.e. that index) into some fieldnames.
madhan ravi
madhan ravi am 16 Mai 2019
Agree with Stephen.

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

madhan ravi
madhan ravi am 15 Mai 2019

0 Stimmen

doc cell2struct

3 Kommentare

Abderrahmane DADA
Abderrahmane DADA am 16 Mai 2019
Thanks Madhan for your input, but I would like to get is, at each iteration "i", the array should be saved directly and named after the index "i".
Ex: i=1 => b (n x n) is computed then savedin the strcture A as A.b1.
i=2 => b (n x n) is computed then savedin the strcture A as A.b2
You now what I mean now?
madhan ravi
madhan ravi am 16 Mai 2019
Bearbeitet: madhan ravi am 16 Mai 2019
A=struct; % an example
for k=1:5
A.(sprintf('b%d',k))=rand(5);
end
Abderrahmane DADA
Abderrahmane DADA am 16 Mai 2019
Thanks a lot Madhan.
That's exactly what I was looking for.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Produkte

Version

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by