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Short code for the expression

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Tino
Tino am 1 Mai 2019
Kommentiert: Guillaume am 1 Mai 2019
h =2;
P = [1, 4, 5, 7];
a1 = (1-h)* 1 + h * P(:, 1);
a2 = (1-h) * a1 + h * P(:, 2);
a3 = (1-h) * a2 + h * P(:, 3);
a4 = (1-h) * a3 + h * P(:, 4);
disp(a1) = 1
disp(a2) = 7
disp(a3) = 3
disp(a4) = 11
  2 Kommentare
Tino
Tino am 1 Mai 2019
Please I will appreciate the answer to this question
thanks in advance
Guillaume
Guillaume am 1 Mai 2019
To what question? You haven't asked anything, just given us some code with no explanation nor context.

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Akzeptierte Antwort

madhan ravi
madhan ravi am 1 Mai 2019
Bearbeitet: madhan ravi am 1 Mai 2019
a = num2cell( (1-h) * repmat( (1-h) * 1 + h * P(1), 1, 4) + h * P ) ;
[a1, a2, a3, a4] = deal( a{:} )
  6 Kommentare
Tino
Tino am 1 Mai 2019
Bearbeitet: Tino am 1 Mai 2019
sorry the right figure is the one below. sorry for giving wrong computation
Can you help me with the short code to gives the following answers for h = any number for instance
when h = 1
1
4
5
7
when h = 2
1
7
7
3
when h = 3
1
10
1
13
thanks in advance
Guillaume
Guillaume am 1 Mai 2019
In your question, you told us than when h = 2, a = [1 7 3 11] (for P = [1, 4, 5, 7]) and this is the answer that my code produces. I have no idea how you get your new answer. It doesn't match the formula you've posted.

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