creating a new column in a matrix using 'if condition"

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Milan Kumar
Milan Kumar am 26 Apr. 2019
Bearbeitet: Stephen23 am 27 Apr. 2019
On the following matrix:
Untitled.png
I am using the following code which is not giving the right response.
if Reg1(:,3)==0
Reg1(:,10)=0;
else
Reg1(:,10)=a1-b1*Reg1(:,3)+Reg1(:,6);
end
Cannot figure out the issue.
The output is
Untitled.png
  1 Kommentar
Catalytic
Catalytic am 26 Apr. 2019
We have no way of knowing what you consider to be the "right response"....

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Stephen23
Stephen23 am 27 Apr. 2019
Bearbeitet: Stephen23 am 27 Apr. 2019
IF will not help you in this situation.
You need to use indexing, e.g.:
Reg1(:,10) = a1-b1*Reg1(:,3) + Reg1(:,6);
idx = Reg1(:,3)==0;
Reg1(idx,10) = 0

Weitere Antworten (1)

Matt J
Matt J am 26 Apr. 2019
Bearbeitet: Matt J am 26 Apr. 2019
if all( Reg1(:,3)==0 )
Reg1(:,10)=0;
else
Reg1(:,10)=a1-b1*Reg1(:,3)+Reg1(:,6);
end

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