ode45 solve and taking current state as input

Hi
Can anyone help me how to fix this problem?
my questions are blow:
this is my function to be solved:
function dx = CSmacro_derive(x,fluid_params,dQ,dV,h_in,dm_in,dm_out)
dx=zeros(3,1);
v=x(1)/x(2);
h=fluid_params.h;
P=fluid_params.P;
dx(1)=dV;
dx(2)=dm_in-dm_out;
dx(3)=(1/(x(2)*fluid_params.dudT))*...
(dQ+((h_in-h)*dm_in)+(P+fluid_params.dudv)*(v*dx(2)-dx(1)));
end
This my main script:
t=linspace(0,10,10);
dV =0.1*sin(t);
dm_in=0.5;
dm_out=0;
% Initial condition
V=0.3326;
m=1;
T=15 + Kel;
x0=[V;m;T];
% Upstream refrigerant
v_in = 0.3326;
T_in = 15 + Kel;
fluid_in = refprop(v_in,T_in,r410a);
h_in=fluid_in.h;
[~,~,dQ] = convecCool(theta_a,x(3),convec_params);
fluid_params = CSmacro_props(x,r410a);
%this is my question.
%how can I take the current x value as my input to these two functions.
for i=length(t)
dx = @(t,x) CSmacro_derive(x,fluid_params,dQ,dV(i),h_in,dm_in,dm_out);
opts=odeset('RelTol',1e-6);
[t,x] = ode45(dx,t,x0,opts);
end
Thanks!

6 Kommentare

Torsten
Torsten am 24 Apr. 2019
By calling "convecCool" and "CSmacro_props" from "CSmacro_derive"
WANYI ZHANG
WANYI ZHANG am 24 Apr. 2019
Can you write a little bit detailed codes?
Thanks a lot
Torsten
Torsten am 24 Apr. 2019
Bearbeitet: Torsten am 24 Apr. 2019
Put the lines marked in bold after the line
function dx = CSmacro_derive(x,fluid_params,dQ,dV,h_in,dm_in,dm_out)
and remove fluid_params,dQ from the list of passed parameters (because they are recalculated now in "CSmacro_derive" for the actual x-vector):
function dx = CSmacro_derive(x,dV,h_in,dm_in,dm_out)
WANYI ZHANG
WANYI ZHANG am 24 Apr. 2019
I fixed it.
but my dV is not passing properly.
Do you know why?
Torsten
Torsten am 24 Apr. 2019
You changed
dx = @(t,x) CSmacro_derive(x,fluid_params,dQ,dV(i),h_in,dm_in,dm_out);
to
dx = @(t,x) CSmacro_derive(x,dV(i),h_in,dm_in,dm_out);
?
Jan
Jan am 24 Apr. 2019
I've formatted the code as code to improve the readability. Please do this by your own in future posts. Thank you.

Melden Sie sich an, um zu kommentieren.

Antworten (0)

Kategorien

Mehr zu Programming finden Sie in Hilfe-Center und File Exchange

Produkte

Version

R2019a

Gefragt:

am 24 Apr. 2019

Kommentiert:

Jan
am 24 Apr. 2019

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by