Compute an Orthogonal Matrix

6 Ansichten (letzte 30 Tage)
namo mah
namo mah am 11 Apr. 2019
Bearbeitet: Matt J am 15 Apr. 2019
Hi All,
I need your help. Is there any solution in Matlab to compute an orthogonal matrix if the first coulomn of the orthogonal matrix is known.
For example, I want to find an orthonal matrix for matrix A,
A = [1 0 0 0 -1 0;-1 1 0 0 0 0;0 -1 1 0 0 0;0 0 -1 1 0 0;0 0 0 -1 1 0;0 0 0 0 -1 1];
U*A*inv(U) = B
U is an orthogonal matrix with the first coulomn of U being [1;1;1;1;1;1] .
B is a diagonal matrix with all eigenvalues of A on the diagonal.
Thank you very much for your help
  5 Kommentare
Matt J
Matt J am 15 Apr. 2019
U is an orthogonal matrix with the first coulomn of U being [1;1;1;1;1;1] .
The norm of the columns (and the rows) of an orthogonal matrix must be one. So, a column of 1's is impossible. Maybe you mean that the column should be [1;1;1;1;1;1] /sqrt(6).
David Goodmanson
David Goodmanson am 15 Apr. 2019
Bearbeitet: David Goodmanson am 15 Apr. 2019
Hi Matt / namo
yes that's true, thanks for pointing it out.
In the specific case of the modified A, there is a U of the right form, but I had not noticed before that it is still not quite right because
U'*A*U = B
whereas the question wanted
U*A*U' = B

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Matt J
Matt J am 15 Apr. 2019
Bearbeitet: Matt J am 15 Apr. 2019
No, this is generally not possible. When all the eigenvalues of A are distinct, for example, the (orthonormalized) eigenvectors are unique up to sign. That means you cannot arbitrarily specify one column of U.

Kategorien

Mehr zu Linear Algebra finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by