hi everyone , i need help to make this , thank u
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mina massoud
am 7 Apr. 2019
Kommentiert: mina massoud
am 7 Apr. 2019
i hava two matrix 2x8
A=2*ones(2,8)
B=3*ones(2,8)
what i need is to access on
1) on each column of matrix A so i need to get out a column vector 2x1 for 8 times to use it in a certain iteration
2) and then on each column of matrix B the same
all of this in the same iteration inside a loop
because if the two matrix are 1x8 it will be easy with two for i=1:8 and j=1:8 (in this case he gave me (1,1) and (1,2) ............ 1,8) then (2,1) ,(2,2) ................. (2,8)) but in this case i need to extract not an element but a column vector.
thank you
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Image Analyst
am 7 Apr. 2019
Bearbeitet: Image Analyst
am 7 Apr. 2019
Example would be good. Plus explain what "access on" means. Do you simple mean
[rows, columns] = size(A);
for col = 1 : columns
thisColA = A(:, col) % Extract column from A.
thisColB = B(:, col) % Extract column from B.
% Now do something .....
end
Akzeptierte Antwort
madhan ravi
am 7 Apr. 2019
No loops needed:
C=permute(reshape([A;B].',size(A,2),size(A,1),[]),[2,1,3]) % C(:,:,1) contains A and 2 B
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