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counting no .of temperature less than 32 in array

1 Ansicht (letzte 30 Tage)
Abhishek singh
Abhishek singh am 3 Apr. 2019
Geschlossen: madhan ravi am 30 Aug. 2020
function numfreeze = freezing(v)
count = 0;
i =v()
j = 32
if i < 32
count = count+1
numfreeze = count
else
end
  1 Kommentar
Abhishek singh
Abhishek singh am 3 Apr. 2019
geeting errror
i =
45 21 32 31 51 12
j =
32
Output argument "numfreeze" (and maybe others) not assigned during call to "freezing".

Antworten (6)

Ngei Katumo
Ngei Katumo am 22 Aug. 2019
function w = freezing (A)
w = sum (logical (A(A<32)));
end

madhan ravi
madhan ravi am 3 Apr. 2019
v=[45 21 32 31 51 12];
threshold=32;
numfreeze = freezing(v,threshold) % function call
function numfreeze = freezing(v,threshold) % function definition
numfreeze = nnz(v<threshold);
end
  6 Kommentare
Image Analyst
Image Analyst am 11 Jun. 2019
You mean freezing.m, since that's what was asked.
madhan ravi
madhan ravi am 15 Sep. 2019
Ah yes exactly:)

Nazneen Sayyad
Nazneen Sayyad am 10 Jun. 2019
Write a function called freezing that takes a vector of numbers that correspond to daily low temperatures in Fahrenheit. Return numfreeze, the number of days with sub freezing temperatures (that is, lower than 32 F) without using loops. Here is an example run:
numfreeze = freezing([45 21 32 31 51 12])
numfreeze =
3
function numfreeze = freezing(A)
B=A(A<32);
numfreeze=numel(B);
end

Ajith Thomas
Ajith Thomas am 19 Jul. 2019
function numfreeze=freezing(w)
lowerthan_32=w(w<32);
no_logical_values=lowerthan_32(lowerthan_32>=0);
numfreeze=length(no_logical_values);
end
  1 Kommentar
Ajith Thomas
Ajith Thomas am 19 Jul. 2019
function numfreeze=freezing(w)
lowerthan_32=w(w<32);
numfreeze=numel(lowerthan_32);
end

Roshan Singh
Roshan Singh am 15 Sep. 2019
function numfreeze = freezing(x)
f = x(x<32);
numfreeze = length(f);
end

MADHURJYA DAS
MADHURJYA DAS am 30 Aug. 2020
function numfreeze=freezing(A)
x=(A<32);
numfreeze=sum(x(:));
end

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R2015b

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