How to save output from loop's eteration into a new matrix.
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Areeb Siraj
am 30 Mär. 2019
Kommentiert: Areeb Siraj
am 31 Mär. 2019
% for I quad
%%co-ordinadets of n and e
n = [-0.557 0.577 0.577 -0.577]; e = [-0.577 -0.577 0.577 0.577];
%%co-ordinadets of x and y
for j=10:10:100 for i=10:10:100 x = [i-10 i i i-10]; y = [j-10 j-10 j j];
A = -0.25*(1-n); B = -0.25*(1-e); C = 0.25*(1-n); D = -0.25*(1+e); E = 0.25*(1+n); F = 0.25*(1+e); G = -0.25*(1+n); H = 0.25*(1-e);
Ia = (A(1,1)*x(1,1)) + (C(1,1)*x(1,2)) + (E(1,1)*x(1,3)) + (G(1,1)*x(1,4)); Ja = (B(1,1)*x(1,1)) + (D(1,1)*x(1,2)) + (F(1,1)*x(1,3)) + (H(1,1)*x(1,4)); Ka = (A(1,1)*y(1,1)) + (C(1,1)*y(1,2)) + (E(1,1)*y(1,3)) + (G(1,1)*y(1,4)); La = (B(1,1)*y(1,1)) + (D(1,1)*y(1,2)) + (F(1,1)*y(1,3)) + (H(1,1)*y(1,4));
% M is jacobian matrix
Ma = [Ia Ja; Ka La]; Na = inv(Ma'); %Mi' = transpose of Jacobian matrix P1a = Na*[A(1,1); B(1,1)]; P2a = Na*[C(1,1); D(1,1)]; P3a = Na*[E(1,1); F(1,1)]; P4a = Na*[G(1,1); H(1,1)];
Qa = [P1a(1,1) 0 P2a(1,1) 0 P3a(1,1) 0 P4a(1,1) 0; 0 P1a(2,1) 0 P2a(2,1) 0 P3a(2,1) 0 P4a(2,1); P1a(2,1) P1a(1,1) P2a(2,1) P2a(1,1) P3a(2,1) P3a(1,1) P4a(2,1) P4a(1,1)]; S = 180; %% value of E = 180 N/mm2 for steel T = 78; %% value of G = 78 N/mm2 for steel U = 34; %% value of poison's ratio V = [(1/S) (-U/S) 0; (-U/S) (1/S) 0; 0 0 (1/T)]; W = inv(V); X1 = 1; %% weighted fucntion w1 X2 = 1; %% weighted fucntion w2 t = 1; %% thickness X3a = det(Ma); %% determinant of jacobian matrix Ya = X1*X2*Qa'*W*Qa*t*X3a;
% for II quad
Ib = (A(1,2)*x(1,1)) + (C(1,2)*x(1,2)) + (E(1,2)*x(1,3)) + (G(1,2)*x(1,4)); Jb = (B(1,2)*x(1,1)) + (D(1,2)*x(1,2)) + (F(1,2)*x(1,3)) + (H(1,2)*x(1,4)); Kb = (A(1,2)*y(1,1)) + (C(1,2)*y(1,2)) + (E(1,2)*y(1,3)) + (G(1,2)*y(1,4)); Lb = (B(1,2)*y(1,1)) + (D(1,2)*y(1,2)) + (F(1,2)*y(1,3)) + (H(1,2)*y(1,4));
% M is jacobian matrix Mb = [Ib Jb; Kb Lb]; Nb = inv(Mb'); %Mi' = transpose of Jacobian matrix P1b = Nb*[A(1,2); B(1,2)]; P2b = Nb*[C(1,2); D(1,2)]; P3b = Nb*[E(1,2); F(1,2)]; P4b = Nb*[G(1,2); H(1,2)];
Qb = [P1b(1,1) 0 P2b(1,1) 0 P3b(1,1) 0 P4b(1,1) 0; 0 P1b(2,1) 0 P2b(2,1) 0 P3b(2,1) 0 P4b(2,1); P1b(2,1) P1b(1,1) P2b(2,1) P2b(1,1) P3b(2,1) P3b(1,1) P4b(2,1) P4b(1,1)]; X3b = det(Mb); %% determinant of jacobian matrix Yb = X1*X2*Qb'*W*Qb*t*X3b;
% for III quad
Ic = (A(1,3)*x(1,1)) + (C(1,3)*x(1,2)) + (E(1,3)*x(1,3)) + (G(1,3)*x(1,4)); Jc = (B(1,3)*x(1,1)) + (D(1,3)*x(1,2)) + (F(1,3)*x(1,3)) + (H(1,3)*x(1,4)); Kc = (A(1,3)*y(1,1)) + (C(1,3)*y(1,2)) + (E(1,3)*y(1,3)) + (G(1,3)*y(1,4)); Lc = (B(1,3)*y(1,1)) + (D(1,3)*y(1,2)) + (F(1,3)*y(1,3)) + (H(1,3)*y(1,4));
% M is jacobian matrix Mc = [Ic Jc; Kc Lc]; Nc = inv(Mc'); %Mi' = transpose of Jacobian matrix P1c = Nc*[A(1,3); B(1,3)]; P2c = Nc*[C(1,3); D(1,3)]; P3c = Nc*[E(1,3); F(1,3)]; P4c = Nc*[G(1,3); H(1,3)];
Qc = [P1c(1,1) 0 P2c(1,1) 0 P3c(1,1) 0 P4c(1,1) 0; 0 P1c(2,1) 0 P2c(2,1) 0 P3c(2,1) 0 P4c(2,1); P1c(2,1) P1c(1,1) P2c(2,1) P2c(1,1) P3c(2,1) P3c(1,1) P4c(2,1) P4c(1,1)]; X3c = det(Mc); %% determinant of jacobian matrix Yc = X1*X2*Qb'*W*Qb*t*X3c;
% for IV quad
Id = (A(1,4)*x(1,1)) + (C(1,4)*x(1,2)) + (E(1,4)*x(1,3)) + (G(1,4)*x(1,4)); Jd = (B(1,4)*x(1,1)) + (D(1,4)*x(1,2)) + (F(1,4)*x(1,3)) + (H(1,4)*x(1,4)); Kd = (A(1,4)*y(1,1)) + (C(1,4)*y(1,2)) + (E(1,4)*y(1,3)) + (G(1,4)*y(1,4)); Ld = (B(1,4)*y(1,1)) + (D(1,4)*y(1,2)) + (F(1,4)*y(1,3)) + (H(1,4)*y(1,4));
% M is jacobian matrix Md = [Id Jd; Kd Ld]; Nd = inv(Md'); %Mi' = transpose of Jacobian matrix P1d = Nd*[A(1,4); B(1,4)]; P2d = Nd*[C(1,4); D(1,4)]; P3d = Nd*[E(1,4); F(1,4)]; P4d = Nd*[G(1,4); H(1,4)];
Qd = [P1d(1,1) 0 P2d(1,1) 0 P3d(1,1) 0 P4d(1,1) 0; 0 P1d(2,1) 0 P2d(2,1) 0 P3d(2,1) 0 P4d(2,1); P1d(2,1) P1d(1,1) P2d(2,1) P2d(1,1) P3d(2,1) P3d(1,1) P4d(2,1) P4d(1,1)]; X3d = det(Md); %% determinant of jacobian matrix Yd = X1*X2*Qd'*W*Qd*t*X3d;
% equvalent matix Yeq = Ya + Yb + Yc + Yd; end end
This is my code and I want save output from loop's eteration in a matrix of size 80 by 80 for further formulation. Such that the first element of this new matrix is the first eteration of loop and so on.
3 Kommentare
Jan
am 30 Mär. 2019
Bearbeitet: Jan
am 30 Mär. 2019
Seriously?
Do not overestimate the willingness of the forum to fix unreadable code, to guess the meaning of vague questions and to follow badly formatted links to not existing web pages. Of course there is no server called "www-mathworks-com-...", but it must be "www.mathworks.com/...".
Akzeptierte Antwort
Rebecca Cleveland Stout
am 30 Mär. 2019
Your code is quite hard to read, but generally, to save elements in a loop, you can do:
A = NaN*ones(80); % preallocate matrix where you want to save stuff
for k = 1:numel(A)
% do your operations
A(k) = result; % save your kth result to element k of the matrix
end
Check out https://www.mathworks.com/matlabcentral/answers/327317-how-to-save-output-of-for-loop if you're still confused.
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