how can i convert c code c code to Mat lab code?
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#include<stdio.h>
#include<math.h>
int main(){
float x1,y1,x2,y2,vx,vy,len,x3,y3,size;
vx=x1-x2;
vy=y1-y2;
len=sqrt((vx*vx)+(vy*vy));
x3=vx/((len*size)+x1);
y3=vy/((len*size)+y1);
float temp1,temp2,angle;
temp1=y3-y1;
temp2=x3-x1;
angle=atan2(temp1,temp2)+1.57;
return 0;
}
4 Kommentare
Anusuya Rajendran
am 27 Mär. 2019
Adam
am 27 Mär. 2019
You need to learn Matlab in that case! There are links to tutorials from the Mathworks website. If you don't knnow how to code Matlab it wouldn't be all that helpful even if someone just does your work for you and converts that one function into Matlab if you have no idea what to do with it anyway.
Image Analyst
am 1 Apr. 2019
Try this Learn MATLAB in 2 hours
Antworten (1)
Jan
am 27 Mär. 2019
This is an invalid C code. You use e.g. x1, x2, size, without defining it. It is meaningless to post the conversion of invalid C code to invalid Matlab code. But if you really want to fail in another language:
vx=x1-x2;
vy=y1-y2;
len=sqrt((vx*vx)+(vy*vy));
x3=vx/((len*size)+x1);
y3=vy/((len*size)+y1);
temp1=y3-y1;
temp2=x3-x1;
angle=atan2(temp1,temp2)+1.57;
That's it - a 1-by-1 copy. Not working also.
2 Kommentare
Walter Roberson
am 1 Apr. 2019
You would probably want to replace the 1.57 with pi/2
Walter Roberson
am 1 Apr. 2019
The code Jan posted is likely not exactly the same as the C code.
The C code uses float for variables. In C, float refers to single precision numbers. MATLAB typically uses double precision instead. To match the C, the code would probably have to deliberately use single() on each input parameters, to force what is likely to be a double precision input to instead use single precision.
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