A={[95],[112],[98],[84],[69],[121],[108]};
B={[1,2,4],[4,3],[6,9,98],[3,7,88],[2,9,1],[55,7],[1,4],[0],[0]};
if size(A,2)<size(B,2)
% add zero at the end of A
end
I want that size of A and B should be the same
result should be
A={[95],[112],[98],[84],[69],[121],[108],[0],[0]};

 Akzeptierte Antwort

Stephen23
Stephen23 am 22 Mär. 2019
Bearbeitet: Stephen23 am 22 Mär. 2019

0 Stimmen

Simple indexing does exactly what you need:
>> A={[95],[112],[98],[84],[69],[121],[108]};
>> B={[1,2,4],[4,3],[6,9,98],[3,7,88],[2,9,1],[55,7],[1,4],[0],[0]};
>> A(end+1:numel(B)) = {[0]};
>> B(end+1:numel(A)) = {[0]};

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