if function for array
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Josefina Ottitsch
am 13 Feb. 2019
Beantwortet: dpb
am 13 Feb. 2019
Hello I have a programm, that looks something like this:
x=[52.23;52.45;56.32;55.48;56.32;53.39;55.53;53.67;57.89]
plot(x)
and now i would like my program to draw the dots of numbers 52 till 54 and 54 till 56 and 56 till 58 in seperate graphs, how do i do this? i wanted to solve this by using if but it doesnt quite work.
thank you for the help!
2 Kommentare
Jan
am 13 Feb. 2019
"solve this by using if but it doesnt quite work" - post the code and the error message. This is much better than letting the readers guiess, what you try and observe.
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dpb
am 13 Feb. 2019
I have a little utility function ("syntax sugar") for such things...
plot(x(iswithin(x,52,54)))
where
>> type iswithin.m
function flg=iswithin(x,lo,hi)
% returns T for values within range of input
% SYNTAX:
% [log] = iswithin(x,lo,hi)
% returns T for x between lo and hi values, inclusive
flg= (x>=lo) & (x<=hi);
>>
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Jan
am 13 Feb. 2019
x=[52.23;52.45;56.32;55.48;56.32;53.39;55.53;53.67;57.89]
subplot(2,2,1)
plot(x)
subplot(2,2,2)
index = find(52 < x && x <= 54);
plot(index, x(index));
subplot(2,2,3)
index = find(54 < x && x <= 56);
plot(index, x(index));
subplot(2,2,4)
index = find(56 < x && x <= 58);
plot(index, x(index));
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