Color detection and display its name
26 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Color detection project
- take colors in circles or squares
- print it
- take a photo of this print
- then put it in your code for color detection
- It should be able to display the name of that color
I have started this project with very simple concept of masking. But colors exists in hundreds or thousands of shades. In my project code should be able to detect any shade and any color. I am thinking to use the concept of Euclidean distance to find the distance of color from origin, but i can not really do it.
If someone could help me please post your solution.
Here is the code i used. it detects only four colors but from one image only.
%------------------------------------
% Read the image into an array.
filename=input('Input the filename of the image>');
RGB = imread(filename);
RGB = imread('D:\College\Project\Project\Cube.png');
%------------------------------------
% Display the original image.
subplot(2, 3, 1);
imshow(RGB);
title('Original RGB Image');
yellowMask = colorDetectHSV(RGB, [0.2 0.9 0], [0.05 0.05 0.05]);
redMask =colorDetectHSV(RGB, [1 1 1], [0.1 0.2 0.2]);
blueMask =colorDetectHSV(RGB, [0.6 0.5 0.6], [0.2 0.3 0.4]);
% Or can try this for blue color:
% blueMask =colorDetectHSV(RGB, [1 0.5 0], [0.4 0.4 0.3]);
greenMask =colorDetectHSV(RGB, [0.369 0.786 0.769], [0.2 0.2 0.2]);
% Display them.
subplot(2, 3, 2);
imshow(yellowMask);
title('Yellow Mask');
subplot(2, 3, 3);
imshow(greenMask);
title('Green Mask');
subplot(2, 3, 4);
imshow(blueMask);
title('Blue Mask');
subplot(2, 3, 5);
imshow(redMask);
title('Red Mask');
3 Kommentare
Antworten (2)
Walter Roberson
am 20 Jul. 2012
Euclidean distance is not enough. Look in the File Exchange for John D'Errico's Fuzzy Color Detection.
But if your task really is to "detect any shade and any color", you should consider giving up before you start any development. Seriously. What you want to do cannot reliably be done. There is no scientific definition for what each color is, or where one shade ends and another begins. And color perception is personal, not absolute. See http://blog.xkcd.com/2010/05/03/color-survey-results/
0 Kommentare
Image Analyst
am 21 Jul. 2012
I have several color detection applications in my File Exchange. http://www.mathworks.com/matlabcentral/fileexchange/?term=authorid%3A31862 Each uses a different method. Feel free to adapt any of them.
5 Kommentare
Navodita Das
am 20 Mai 2020
Suppose, an image contains red point in it. Can I set that red point as origin of coordinate system?
Siehe auch
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!