why eq says they are not equal

I have two equal vectors a = b. When I check for equality:
y = eq(a, b)
find(y==0)
I get most of values, meaning they are NOT equal.
What would be the reason for this?
N.

5 Kommentare

Jan
Jan am 19 Jul. 2012
What does the "find(a==0)" do in your code?
Nuchto
Nuchto am 21 Jul. 2012
Sorry, it was wrong put, "a" should be the output of eq(a,b).
Jan
Jan am 21 Jul. 2012
Then please edit the question instead of adding this important information as a comment.
Nuchto
Nuchto am 22 Jul. 2012
Thanks, I did.
Jan
Jan am 22 Jul. 2012
@Nuchto: Is your problem solved?

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

Muruganandham Subramanian
Muruganandham Subramanian am 19 Jul. 2012
Bearbeitet: Walter Roberson am 22 Jul. 2012

0 Stimmen

Hi Nuchto,
Check this below link:

1 Kommentar

Nuchto
Nuchto am 19 Jul. 2012
I have checked the help, but it didn't answer to my question.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (2)

Jan
Jan am 19 Jul. 2012
Bearbeitet: Jan am 19 Jul. 2012

0 Stimmen

To compare two vectors use:
r = isequal(a, b)
or to find the difference between vectors (or other arrays) of the same size:
any(a - b)
Note, that the later replies FALSE even for ones(1,10) and ones(1,1).
If you only assume, that the vectors have equal values, check a - b and note, that the limited precision of the type double leads to effects like:
03. - 0.2 ~= 0.1
Then check "almost equal" by:
limit = eps(max(max(abs(a(:)), abs(b(:)))));
% or: eps(max(abs(a(:)), abs(b(:))));
% or: the same times 10
a_eq_b = isequal(size(a), size(b)) & all(abs(a - b) < limit);
The choise of the limit depends on the physical meaning of the variables. There is no unique definition to distinguish measurement noise from noise caused by numerical artifacts for a tiny values.

Kategorien

Mehr zu Programming finden Sie in Hilfe-Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by