Add new elements into cell array inside a loop
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Hello all!
I I have a set of 10000 values and according to the thresholds I am setting I want to seperate them into individual matrices that would be inside the cell. The matrices elements are distributed trough a loop as above:
for i=1:1:length(TestData)
for k=1:1:4
if TestData(i,3)>=low(k,1) && TestData(i,3)<=high(k,1)
CreatedCell{k}=TestData(i,:);
end
end
end
So how could I store my data into the cell and create multiple matrices? With the way I am doing it now it stores only the last value but I need to store the whole matrices.
3 Kommentare
Guillaume
am 14 Jan. 2019
The first issue is that you're using length as a synonym for the number of rows on something that is clearly a matrix. length returns the number of rows or columns, whichever is greater, so you're taking a risk. It would be much better to use size(TestData, 1) to ensure you always get the number of rows.
What does it doesn't work mean? If you get an error, what is the full text of the error? If you don't get the result you expect, then what exactly did you expect and what did you get instead.
Antworten (1)
Stephen23
am 14 Jan. 2019
Bearbeitet: Stephen23
am 14 Jan. 2019
This will store the data each iteration of both loops (but I did not change the logical conditions):
N = size(TestData,1); % much better than length
C = cell(N,4);
for ii = 1:N
for jj = 1:4
if TestData(ii,3)>=low(jj,1) && TestData(ii,3)<=high(jj,1)
C{ii,jj} = TestData(ii,:);
end
end
end
Note that this can create copies of the same data in the cell array. This may or may not be what you expect (it is not clear from your question).
4 Kommentare
Stephen23
am 14 Jan. 2019
Bearbeitet: Stephen23
am 14 Jan. 2019
>> TD = randi([1,100],10000,1); % fake data: random integers [1,100].
>> B = 1:20:101; % bin lower edges.
>> [bin,idx] = histc(TD,B); % match data to bins: B(n)<=data<B(n+1).
>> C = accumarray(idx,TD,[],@(v){v}); % split data according to matched bins.
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