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Copy file from one directory to another

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Marisabel Gonzalez
Marisabel Gonzalez on 17 Dec 2018
Answered: Prajwol Tamrakar on 27 May 2020
Hi,
So I am using this piece of code to copy some files with similar names from several destination paths (e.g. file03431314, file6767464363, etc).
When I use 'file*' it assumes it is a directory, which is not...
When I actualy copy and paste the filename, e.g. 'file03431314', it works fine.
PS: the file that I want to copy does not have an extension.
How can I fix this?
Thanks
p1 = 'filepath'
% Copying file from respective path
pdest = 'mydestinationpath';
filename = 'file*';
source = fullfile(p1,filename);
destination = fullfile(pdest,filename);
copyfile(source,destination)
% Renaming
oldname = filename;
newname = '1_file.txt';
copyfile(oldname,newname);
% Deleting old file
delete(filename)

  1 Comment

Jan
Jan on 17 Dec 2018
What does this mean:
When I use 'file*' it assumes it is a directory, which is not...
What are the "it"s and why do you assume that it assumes that what is a directory?
Is renaming the files a part of the question?

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Answers (3)

Jan
Jan on 17 Dec 2018
If there are really problems with the copy of a file pattern, do it explicitly with a loop:
psource = 'filepath'
pdest = 'mydestinationpath';
pattern = 'file*';
sourceDir = dir(fullfile(psource, pattern));
sourceDir([sourceDir.isdir]) = []; % Files only
for k = 1:numel(sourceDir)
sourceFile = fullfile(psource, sourceDir(k).name);
destFile = fullfile(pdest, sourceDir(k).name); % Or another name?
movefile(sourceFile, destFile);
end

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Prajwol Tamrakar
Prajwol Tamrakar on 27 May 2020
This issue of copying file to another directory is possibly due to "ready only access". Use 'f' option to override the read-only status of the destination folder.
copyfile(SourceFile, DestinyFile, 'f')

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Omer Yasin Birey
Omer Yasin Birey on 17 Dec 2018
Maybe you can get parts of the filename by using
[filepath,name,ext] = fileparts(file);
and after that you can use directly the name of the file instead of this "filename = 'file*';"
[filepath,name,ext] = fileparts(file);
filepath =
'H:\user4\matlab'
name =
'myfile'
ext =
'.txt'
once you get the name of the file by this, you can use it in your code.

  2 Comments

Marisabel Gonzalez
Marisabel Gonzalez on 17 Dec 2018
It's not just one file. I'm running simulations and I want to save the output files. All of them start with the same name but then are followed by a series of numbers. Also, the files don't have an extension. I save it as .txt but the original file doesn't have any extension.
Omer Yasin Birey
Omer Yasin Birey on 17 Dec 2018
filename = 'file';
numbers = [1 2 3 4 5 1234324123 03431314 3431314123123 ..... ]
for i = 1:length(k)
nFile{i} = sprintf('%s_%d',filename,numbers(i));
end

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