How to get the columns of non zero matrix?

I have a matrix named A

a= [1  0  0  0  0  0  0  0  0  0;
    0  0  0  0  0  0  0  0  0  0;
    0  1  0  0  0  0  0  0  0  0;
    0  0  1  0  0  0  0  0  0  0;
    0  0  0  1  0  0  0  0  0  0;
    0  0  0  0  1  0  0  0  0  0;
    0  0  0  0  0  1  0  0  0  0;
    0  0  0  0  0  0  1  1  0  0;
    0  0  0  0  0  0  0  0  1  1];

How can I have the number of column of non-zero number in a matrix? (Check by rows)

The result would be

Column = [1 0 2 3 4 5 6 7  8 9 1 0]

[Adam Danz]

I don't understand the quesiton. Is the output merely 1,2,3,4,5,6,7,8,9,10? Are you just cumulatively counting the number of 1s by row?

What would be the result of this input?

a = [ 1 0 1 1; 
      0 0 0 1; 
      0 0 0 0; 
      1 1 1 1]; 
  

Answer 1

[YT]

Your example is a bit vague, but if the main question is to find the non-zero values in the matrix, I would suggest using the following

[r c] = find(a~=0) %returns rows (r) and columns (c) of non-zero values