How to change matrix numbers positions

I have a matrix generated randomly and I want to change the positions of the numbers
i.e:
X=[2 3 4 5;
7 8 9 1]
to
X=[9 5 1 3;
5 2 8 2]
(I'm the one who chooses the new positions, not random)

Antworten (3)

Georgios Pyrgiotakis
Georgios Pyrgiotakis am 30 Nov. 2018

0 Stimmen

do you mean that you want to randomly reanrage the array?
Image Analyst
Image Analyst am 30 Nov. 2018

0 Stimmen

Will this work for you?
X = [2 3 4 5;
7 8 9 1]
[rows, columns] = size(X)
X = X(randperm(numel(X))) % Unfortunately reshapes into a row vector.
X = reshape(X, [rows, columns]) % Put back into 2-D
It rearranges elements into a random order.

2 Kommentare

Hugo Matias
Hugo Matias am 30 Nov. 2018
No, i'm the one who chooses the new positions!
Image Analyst
Image Analyst am 30 Nov. 2018
What form do you have your new positions in? A matrix? A vector? Two vectors or two matrices with new rows in one, and new columns in the other? Come on, make it EASY for us to help you, not hard.

Melden Sie sich an, um zu kommentieren.

Bruno Luong
Bruno Luong am 30 Nov. 2018

0 Stimmen

X(randperm(numel(X))) = X

4 Kommentare

Hugo Matias
Hugo Matias am 30 Nov. 2018
i'm the one who chooses the new positions!
Bruno Luong
Bruno Luong am 30 Nov. 2018
Bearbeitet: Bruno Luong am 30 Nov. 2018
Even easier:
X(:) = X(TheNewPositionYouChoose)
Hugo Matias
Hugo Matias am 30 Nov. 2018
How would I do if I wanted to to change the position of the number at (1,2) to (2,3) , for example?
Bruno Luong
Bruno Luong am 30 Nov. 2018
Put 3 in NewPositionYouChoose(6)

Melden Sie sich an, um zu kommentieren.

Kategorien

Gefragt:

am 30 Nov. 2018

Kommentiert:

am 30 Nov. 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by